Metamath Proof Explorer


Theorem lpadlem3

Description: Lemma for lpadlen1 . (Contributed by Thierry Arnoux, 7-Aug-2023)

Ref Expression
Hypotheses lpadlen.1 φL0
lpadlen.2 φWWordS
lpadlen.3 φCS
lpadlen1.1 φLW
Assertion lpadlem3 φ0..^LW×C=

Proof

Step Hyp Ref Expression
1 lpadlen.1 φL0
2 lpadlen.2 φWWordS
3 lpadlen.3 φCS
4 lpadlen1.1 φLW
5 lencl WWordSW0
6 2 5 syl φW0
7 6 nn0zd φW
8 1 nn0zd φL
9 fzo0n WLLW0..^LW=
10 9 biimpa WLLW0..^LW=
11 7 8 4 10 syl21anc φ0..^LW=
12 11 xpeq1d φ0..^LW×C=×C
13 0xp ×C=
14 12 13 eqtrdi φ0..^LW×C=