Metamath Proof Explorer


Theorem lsmsnidl

Description: The product of the ring with a single element is a principal ideal. (Contributed by Thierry Arnoux, 21-Jan-2024)

Ref Expression
Hypotheses lsmsnpridl.1 ⊢ B = Base R
lsmsnpridl.2 ⊢ G = mulGrp R
lsmsnpridl.3 ⊢ × ˙ = LSSum ⁡ G
lsmsnpridl.4 ⊢ K = RSpan ⁡ R
lsmsnpridl.5 ⊢ φ → R ∈ Ring
lsmsnpridl.6 ⊢ φ → X ∈ B
Assertion lsmsnidl ⊢ φ → B × ˙ X ∈ LPIdeal ⁡ R

Proof

Step Hyp Ref Expression
1 lsmsnpridl.1 ⊢ B = Base R
2 lsmsnpridl.2 ⊢ G = mulGrp R
3 lsmsnpridl.3 ⊢ × ˙ = LSSum ⁡ G
4 lsmsnpridl.4 ⊢ K = RSpan ⁡ R
5 lsmsnpridl.5 ⊢ φ → R ∈ Ring
6 lsmsnpridl.6 ⊢ φ → X ∈ B
7 sneq ⊢ y = X → y = X
8 7 fveq2d ⊢ y = X → K ⁡ y = K ⁡ X
9 8 eqeq2d ⊢ y = X → B × ˙ X = K ⁡ y ↔ B × ˙ X = K ⁡ X
10 9 adantl ⊢ φ ∧ y = X → B × ˙ X = K ⁡ y ↔ B × ˙ X = K ⁡ X
11 1 2 3 4 5 6 lsmsnpridl ⊢ φ → B × ˙ X = K ⁡ X
12 6 10 11 rspcedvd ⊢ φ → ∃ y ∈ B B × ˙ X = K ⁡ y
13 eqid ⊢ LPIdeal ⁡ R = LPIdeal ⁡ R
14 13 4 1 islpidl ⊢ R ∈ Ring → B × ˙ X ∈ LPIdeal ⁡ R ↔ ∃ y ∈ B B × ˙ X = K ⁡ y
15 5 14 syl ⊢ φ → B × ˙ X ∈ LPIdeal ⁡ R ↔ ∃ y ∈ B B × ˙ X = K ⁡ y
16 12 15 mpbird ⊢ φ → B × ˙ X ∈ LPIdeal ⁡ R