Metamath Proof Explorer


Theorem lsmss2b

Description: Subgroup sum with a subset. (Contributed by NM, 10-Jan-2015) (Revised by Mario Carneiro, 19-Apr-2016)

Ref Expression
Hypothesis lsmub1.p ⊢ ⊕ ˙ = LSSum ⁡ G
Assertion lsmss2b ⊢ T ∈ SubGrp ⁡ G ∧ U ∈ SubGrp ⁡ G → U ⊆ T ↔ T ⊕ ˙ U = T

Proof

Step Hyp Ref Expression
1 lsmub1.p ⊢ ⊕ ˙ = LSSum ⁡ G
2 1 lsmss2 ⊢ T ∈ SubGrp ⁡ G ∧ U ∈ SubGrp ⁡ G ∧ U ⊆ T → T ⊕ ˙ U = T
3 2 3expia ⊢ T ∈ SubGrp ⁡ G ∧ U ∈ SubGrp ⁡ G → U ⊆ T → T ⊕ ˙ U = T
4 1 lsmub2 ⊢ T ∈ SubGrp ⁡ G ∧ U ∈ SubGrp ⁡ G → U ⊆ T ⊕ ˙ U
5 sseq2 ⊢ T ⊕ ˙ U = T → U ⊆ T ⊕ ˙ U ↔ U ⊆ T
6 4 5 syl5ibcom ⊢ T ∈ SubGrp ⁡ G ∧ U ∈ SubGrp ⁡ G → T ⊕ ˙ U = T → U ⊆ T
7 3 6 impbid ⊢ T ∈ SubGrp ⁡ G ∧ U ∈ SubGrp ⁡ G → U ⊆ T ↔ T ⊕ ˙ U = T