Metamath Proof Explorer


Theorem lss0ss

Description: The zero subspace is included in every subspace. ( sh0le analog.) (Contributed by NM, 27-Mar-2014) (Revised by Mario Carneiro, 19-Jun-2014)

Ref Expression
Hypotheses lss0cl.z ⊢ 0 ˙ = 0 W
lss0cl.s ⊢ S = LSubSp ⁡ W
Assertion lss0ss ⊢ W ∈ LMod ∧ X ∈ S → 0 ˙ ⊆ X

Proof

Step Hyp Ref Expression
1 lss0cl.z ⊢ 0 ˙ = 0 W
2 lss0cl.s ⊢ S = LSubSp ⁡ W
3 1 2 lss0cl ⊢ W ∈ LMod ∧ X ∈ S → 0 ˙ ∈ X
4 3 snssd ⊢ W ∈ LMod ∧ X ∈ S → 0 ˙ ⊆ X