Metamath Proof Explorer


Theorem lss0cl

Description: The zero vector belongs to every subspace. (Contributed by NM, 12-Jan-2014) (Proof shortened by Mario Carneiro, 19-Jun-2014)

Ref Expression
Hypotheses lss0cl.z ⊢ 0 ˙ = 0 W
lss0cl.s ⊢ S = LSubSp ⁡ W
Assertion lss0cl ⊢ W ∈ LMod ∧ U ∈ S → 0 ˙ ∈ U

Proof

Step Hyp Ref Expression
1 lss0cl.z ⊢ 0 ˙ = 0 W
2 lss0cl.s ⊢ S = LSubSp ⁡ W
3 2 lssn0 ⊢ U ∈ S → U ≠ ∅
4 n0 ⊢ U ≠ ∅ ↔ ∃ x x ∈ U
5 3 4 sylib ⊢ U ∈ S → ∃ x x ∈ U
6 5 adantl ⊢ W ∈ LMod ∧ U ∈ S → ∃ x x ∈ U
7 simp1 ⊢ W ∈ LMod ∧ U ∈ S ∧ x ∈ U → W ∈ LMod
8 eqid ⊢ Base W = Base W
9 8 2 lssel ⊢ U ∈ S ∧ x ∈ U → x ∈ Base W
10 9 3adant1 ⊢ W ∈ LMod ∧ U ∈ S ∧ x ∈ U → x ∈ Base W
11 eqid ⊢ - W = - W
12 8 1 11 lmodsubid ⊢ W ∈ LMod ∧ x ∈ Base W → x - W x = 0 ˙
13 7 10 12 syl2anc ⊢ W ∈ LMod ∧ U ∈ S ∧ x ∈ U → x - W x = 0 ˙
14 11 2 lssvsubcl ⊢ W ∈ LMod ∧ U ∈ S ∧ x ∈ U ∧ x ∈ U → x - W x ∈ U
15 14 anabsan2 ⊢ W ∈ LMod ∧ U ∈ S ∧ x ∈ U → x - W x ∈ U
16 15 3impa ⊢ W ∈ LMod ∧ U ∈ S ∧ x ∈ U → x - W x ∈ U
17 13 16 eqeltrrd ⊢ W ∈ LMod ∧ U ∈ S ∧ x ∈ U → 0 ˙ ∈ U
18 17 3expia ⊢ W ∈ LMod ∧ U ∈ S → x ∈ U → 0 ˙ ∈ U
19 18 exlimdv ⊢ W ∈ LMod ∧ U ∈ S → ∃ x x ∈ U → 0 ˙ ∈ U
20 6 19 mpd ⊢ W ∈ LMod ∧ U ∈ S → 0 ˙ ∈ U