Metamath Proof Explorer


Theorem midid

Description: Midpoint of a null segment. (Contributed by Thierry Arnoux, 7-Dec-2019)

Ref Expression
Hypotheses ismid.p ⊢ P = Base G
ismid.d ⊢ - ˙ = dist ⁡ G
ismid.i ⊢ I = Itv ⁡ G
ismid.g ⊢ φ → G ∈ 𝒢 Tarski
ismid.1 ⊢ φ → G Dim 𝒢 ≥ 2
midcl.1 ⊢ φ → A ∈ P
midcl.2 ⊢ φ → B ∈ P
Assertion midid ⊢ φ → A mid 𝒢 ⁡ G A = A

Proof

Step Hyp Ref Expression
1 ismid.p ⊢ P = Base G
2 ismid.d ⊢ - ˙ = dist ⁡ G
3 ismid.i ⊢ I = Itv ⁡ G
4 ismid.g ⊢ φ → G ∈ 𝒢 Tarski
5 ismid.1 ⊢ φ → G Dim 𝒢 ≥ 2
6 midcl.1 ⊢ φ → A ∈ P
7 midcl.2 ⊢ φ → B ∈ P
8 1 2 3 4 5 6 6 midcl ⊢ φ → A mid 𝒢 ⁡ G A ∈ P
9 1 2 3 4 5 6 6 midbtwn ⊢ φ → A mid 𝒢 ⁡ G A ∈ A I A
10 1 2 3 4 6 8 9 axtgbtwnid ⊢ φ → A = A mid 𝒢 ⁡ G A
11 10 eqcomd ⊢ φ → A mid 𝒢 ⁡ G A = A