Metamath Proof Explorer


Theorem mircgrextend

Description: Link congruence over a pair of mirror points. cf tgcgrextend . (Contributed by Thierry Arnoux, 4-Oct-2020)

Ref Expression
Hypotheses mirval.p ⊢ P = Base G
mirval.d ⊢ - ˙ = dist ⁡ G
mirval.i ⊢ I = Itv ⁡ G
mirval.l ⊢ L = Line 𝒢 ⁡ G
mirval.s ⊢ S = pInv 𝒢 ⁡ G
mirval.g ⊢ φ → G ∈ 𝒢 Tarski
mirtrcgr.e ⊢ ∼ ˙ = ∼ 𝒢 ⁡ G
mirtrcgr.m ⊢ M = S ⁡ B
mirtrcgr.n ⊢ N = S ⁡ Y
mirtrcgr.a ⊢ φ → A ∈ P
mirtrcgr.b ⊢ φ → B ∈ P
mirtrcgr.x ⊢ φ → X ∈ P
mirtrcgr.y ⊢ φ → Y ∈ P
mircgrextend.1 ⊢ φ → A - ˙ B = X - ˙ Y
Assertion mircgrextend ⊢ φ → A - ˙ M ⁡ A = X - ˙ N ⁡ X

Proof

Step Hyp Ref Expression
1 mirval.p ⊢ P = Base G
2 mirval.d ⊢ - ˙ = dist ⁡ G
3 mirval.i ⊢ I = Itv ⁡ G
4 mirval.l ⊢ L = Line 𝒢 ⁡ G
5 mirval.s ⊢ S = pInv 𝒢 ⁡ G
6 mirval.g ⊢ φ → G ∈ 𝒢 Tarski
7 mirtrcgr.e ⊢ ∼ ˙ = ∼ 𝒢 ⁡ G
8 mirtrcgr.m ⊢ M = S ⁡ B
9 mirtrcgr.n ⊢ N = S ⁡ Y
10 mirtrcgr.a ⊢ φ → A ∈ P
11 mirtrcgr.b ⊢ φ → B ∈ P
12 mirtrcgr.x ⊢ φ → X ∈ P
13 mirtrcgr.y ⊢ φ → Y ∈ P
14 mircgrextend.1 ⊢ φ → A - ˙ B = X - ˙ Y
15 1 2 3 4 5 6 11 8 10 mircl ⊢ φ → M ⁡ A ∈ P
16 1 2 3 4 5 6 13 9 12 mircl ⊢ φ → N ⁡ X ∈ P
17 1 2 3 4 5 6 11 8 10 mirbtwn ⊢ φ → B ∈ M ⁡ A I A
18 1 2 3 6 15 11 10 17 tgbtwncom ⊢ φ → B ∈ A I M ⁡ A
19 1 2 3 4 5 6 13 9 12 mirbtwn ⊢ φ → Y ∈ N ⁡ X I X
20 1 2 3 6 16 13 12 19 tgbtwncom ⊢ φ → Y ∈ X I N ⁡ X
21 1 2 3 6 10 11 12 13 14 tgcgrcomlr ⊢ φ → B - ˙ A = Y - ˙ X
22 1 2 3 4 5 6 11 8 10 mircgr ⊢ φ → B - ˙ M ⁡ A = B - ˙ A
23 1 2 3 4 5 6 13 9 12 mircgr ⊢ φ → Y - ˙ N ⁡ X = Y - ˙ X
24 21 22 23 3eqtr4d ⊢ φ → B - ˙ M ⁡ A = Y - ˙ N ⁡ X
25 1 2 3 6 10 11 15 12 13 16 18 20 14 24 tgcgrextend ⊢ φ → A - ˙ M ⁡ A = X - ˙ N ⁡ X