Metamath Proof Explorer


Theorem msubf

Description: A substitution is a function. (Contributed by Mario Carneiro, 18-Jul-2016)

Ref Expression
Hypotheses msubco.s ⊢ S = mSubst ⁡ T
msubf.e ⊢ E = mEx ⁡ T
Assertion msubf ⊢ F ∈ ran ⁡ S → F : E ⟶ E

Proof

Step Hyp Ref Expression
1 msubco.s ⊢ S = mSubst ⁡ T
2 msubf.e ⊢ E = mEx ⁡ T
3 n0i ⊢ F ∈ ran ⁡ S → ¬ ran ⁡ S = ∅
4 1 rnfvprc ⊢ ¬ T ∈ V → ran ⁡ S = ∅
5 3 4 nsyl2 ⊢ F ∈ ran ⁡ S → T ∈ V
6 eqid ⊢ mVR ⁡ T = mVR ⁡ T
7 eqid ⊢ mREx ⁡ T = mREx ⁡ T
8 6 7 1 2 msubff ⊢ T ∈ V → S : mREx ⁡ T ↑ 𝑝𝑚 mVR ⁡ T ⟶ E E
9 frn ⊢ S : mREx ⁡ T ↑ 𝑝𝑚 mVR ⁡ T ⟶ E E → ran ⁡ S ⊆ E E
10 5 8 9 3syl ⊢ F ∈ ran ⁡ S → ran ⁡ S ⊆ E E
11 id ⊢ F ∈ ran ⁡ S → F ∈ ran ⁡ S
12 10 11 sseldd ⊢ F ∈ ran ⁡ S → F ∈ E E
13 elmapi ⊢ F ∈ E E → F : E ⟶ E
14 12 13 syl ⊢ F ∈ ran ⁡ S → F : E ⟶ E