Metamath Proof Explorer


Theorem muldmmbl

Description: If two functions have domains in the sigma-algebra, the domain of their multiplication also belongs to the sigma-algebra. This is the second statement of Proposition 121H of Fremlin1, p. 39. Note: While the theorem in the book assumes the functions are sigma-measurable, this assumption is unnecessary for the part concerning their multiplication. (Contributed by Glauco Siliprandi, 30-Dec-2024)

Ref Expression
Hypotheses muldmmbl.1 ⊢ Ⅎ x φ
muldmmbl.2 ⊢ Ⅎ _ x A
muldmmbl.3 ⊢ Ⅎ _ x B
muldmmbl.4 ⊢ φ → S ∈ SAlg
muldmmbl.5 ⊢ φ → A ∈ S
muldmmbl.6 ⊢ φ → B ∈ S
Assertion muldmmbl ⊢ φ → dom ⁡ x ∈ A ∩ B ⟼ C ⁢ D ∈ S

Proof

Step Hyp Ref Expression
1 muldmmbl.1 ⊢ Ⅎ x φ
2 muldmmbl.2 ⊢ Ⅎ _ x A
3 muldmmbl.3 ⊢ Ⅎ _ x B
4 muldmmbl.4 ⊢ φ → S ∈ SAlg
5 muldmmbl.5 ⊢ φ → A ∈ S
6 muldmmbl.6 ⊢ φ → B ∈ S
7 2 3 nfin ⊢ Ⅎ _ x A ∩ B
8 eqid ⊢ x ∈ A ∩ B ⟼ C ⁢ D = x ∈ A ∩ B ⟼ C ⁢ D
9 ovexd ⊢ φ ∧ x ∈ A ∩ B → C ⁢ D ∈ V
10 1 7 8 9 dmmptdff ⊢ φ → dom ⁡ x ∈ A ∩ B ⟼ C ⁢ D = A ∩ B
11 4 5 6 salincld ⊢ φ → A ∩ B ∈ S
12 10 11 eqeltrd ⊢ φ → dom ⁡ x ∈ A ∩ B ⟼ C ⁢ D ∈ S