Metamath Proof Explorer


Theorem mvlrmuld

Description: Move the right term in a product on the LHS to the RHS, deduction form. (Contributed by David A. Wheeler, 11-Oct-2018)

Ref Expression
Hypotheses mvlrmuld.1 ⊢ φ → A ∈ ℂ
mvlrmuld.2 ⊢ φ → B ∈ ℂ
mvlrmuld.3 ⊢ φ → B ≠ 0
mvlrmuld.4 ⊢ φ → A ⁢ B = C
Assertion mvlrmuld ⊢ φ → A = C B

Proof

Step Hyp Ref Expression
1 mvlrmuld.1 ⊢ φ → A ∈ ℂ
2 mvlrmuld.2 ⊢ φ → B ∈ ℂ
3 mvlrmuld.3 ⊢ φ → B ≠ 0
4 mvlrmuld.4 ⊢ φ → A ⁢ B = C
5 1 2 3 divcan4d ⊢ φ → A ⁢ B B = A
6 4 oveq1d ⊢ φ → A ⁢ B B = C B
7 5 6 eqtr3d ⊢ φ → A = C B