Metamath Proof Explorer


Theorem ngpds

Description: Value of the distance function in terms of the norm of a normed group. Equation 1 of Kreyszig p. 59. (Contributed by NM, 28-Nov-2006) (Revised by Mario Carneiro, 2-Oct-2015)

Ref Expression
Hypotheses ngpds.n ⊢ N = norm ⁡ G
ngpds.x ⊢ X = Base G
ngpds.m ⊢ - ˙ = - G
ngpds.d ⊢ D = dist ⁡ G
Assertion ngpds ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → A D B = N ⁡ A - ˙ B

Proof

Step Hyp Ref Expression
1 ngpds.n ⊢ N = norm ⁡ G
2 ngpds.x ⊢ X = Base G
3 ngpds.m ⊢ - ˙ = - G
4 ngpds.d ⊢ D = dist ⁡ G
5 eqid ⊢ D ↾ X × X = D ↾ X × X
6 1 3 4 2 5 isngp2 ⊢ G ∈ NrmGrp ↔ G ∈ Grp ∧ G ∈ MetSp ∧ N ∘ - ˙ = D ↾ X × X
7 6 simp3bi ⊢ G ∈ NrmGrp → N ∘ - ˙ = D ↾ X × X
8 7 3ad2ant1 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → N ∘ - ˙ = D ↾ X × X
9 8 oveqd ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → A N ∘ - ˙ B = A D ↾ X × X B
10 ngpgrp ⊢ G ∈ NrmGrp → G ∈ Grp
11 2 3 grpsubf ⊢ G ∈ Grp → - ˙ : X × X ⟶ X
12 10 11 syl ⊢ G ∈ NrmGrp → - ˙ : X × X ⟶ X
13 12 3ad2ant1 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → - ˙ : X × X ⟶ X
14 opelxpi ⊢ A ∈ X ∧ B ∈ X → A B ∈ X × X
15 14 3adant1 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → A B ∈ X × X
16 fvco3 ⊢ - ˙ : X × X ⟶ X ∧ A B ∈ X × X → N ∘ - ˙ ⁡ A B = N ⁡ - ˙ ⁡ A B
17 13 15 16 syl2anc ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → N ∘ - ˙ ⁡ A B = N ⁡ - ˙ ⁡ A B
18 df-ov ⊢ A N ∘ - ˙ B = N ∘ - ˙ ⁡ A B
19 df-ov ⊢ A - ˙ B = - ˙ ⁡ A B
20 19 fveq2i ⊢ N ⁡ A - ˙ B = N ⁡ - ˙ ⁡ A B
21 17 18 20 3eqtr4g ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → A N ∘ - ˙ B = N ⁡ A - ˙ B
22 ovres ⊢ A ∈ X ∧ B ∈ X → A D ↾ X × X B = A D B
23 22 3adant1 ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → A D ↾ X × X B = A D B
24 9 21 23 3eqtr3rd ⊢ G ∈ NrmGrp ∧ A ∈ X ∧ B ∈ X → A D B = N ⁡ A - ˙ B