Metamath Proof Explorer


Theorem opsrbaslem

Description: Get a component of the ordered power series structure. (Contributed by Mario Carneiro, 8-Feb-2015) (Revised by Mario Carneiro, 2-Oct-2015) (Revised by AV, 9-Sep-2021) (Revised by AV, 1-Nov-2024)

Ref Expression
Hypotheses opsrbas.s ⊢ S = I mPwSer R
opsrbas.o ⊢ O = I ordPwSer R ⁡ T
opsrbas.t ⊢ φ → T ⊆ I × I
opsrbaslem.1 ⊢ E = Slot E ⁡ ndx
opsrbaslem.2 ⊢ E ⁡ ndx ≠ ≤ ndx
Assertion opsrbaslem ⊢ φ → E ⁡ S = E ⁡ O

Proof

Step Hyp Ref Expression
1 opsrbas.s ⊢ S = I mPwSer R
2 opsrbas.o ⊢ O = I ordPwSer R ⁡ T
3 opsrbas.t ⊢ φ → T ⊆ I × I
4 opsrbaslem.1 ⊢ E = Slot E ⁡ ndx
5 opsrbaslem.2 ⊢ E ⁡ ndx ≠ ≤ ndx
6 4 5 setsnid ⊢ E ⁡ S = E ⁡ S sSet ≤ ndx ≤ O
7 eqid ⊢ ≤ O = ≤ O
8 simprl ⊢ φ ∧ I ∈ V ∧ R ∈ V → I ∈ V
9 simprr ⊢ φ ∧ I ∈ V ∧ R ∈ V → R ∈ V
10 3 adantr ⊢ φ ∧ I ∈ V ∧ R ∈ V → T ⊆ I × I
11 1 2 7 8 9 10 opsrval2 ⊢ φ ∧ I ∈ V ∧ R ∈ V → O = S sSet ≤ ndx ≤ O
12 11 fveq2d ⊢ φ ∧ I ∈ V ∧ R ∈ V → E ⁡ O = E ⁡ S sSet ≤ ndx ≤ O
13 6 12 eqtr4id ⊢ φ ∧ I ∈ V ∧ R ∈ V → E ⁡ S = E ⁡ O
14 0fv ⊢ ∅ ⁡ T = ∅
15 14 eqcomi ⊢ ∅ = ∅ ⁡ T
16 reldmpsr ⊢ Rel ⁡ dom ⁡ mPwSer
17 16 ovprc ⊢ ¬ I ∈ V ∧ R ∈ V → I mPwSer R = ∅
18 reldmopsr ⊢ Rel ⁡ dom ⁡ ordPwSer
19 18 ovprc ⊢ ¬ I ∈ V ∧ R ∈ V → I ordPwSer R = ∅
20 19 fveq1d ⊢ ¬ I ∈ V ∧ R ∈ V → I ordPwSer R ⁡ T = ∅ ⁡ T
21 15 17 20 3eqtr4a ⊢ ¬ I ∈ V ∧ R ∈ V → I mPwSer R = I ordPwSer R ⁡ T
22 21 1 2 3eqtr4g ⊢ ¬ I ∈ V ∧ R ∈ V → S = O
23 22 fveq2d ⊢ ¬ I ∈ V ∧ R ∈ V → E ⁡ S = E ⁡ O
24 23 adantl ⊢ φ ∧ ¬ I ∈ V ∧ R ∈ V → E ⁡ S = E ⁡ O
25 13 24 pm2.61dan ⊢ φ → E ⁡ S = E ⁡ O