Metamath Proof Explorer


Theorem ovima0

Description: An operation value is a member of the image plus null. (Contributed by Thierry Arnoux, 25-Jun-2019)

Ref Expression
Assertion ovima0 ⊢ X ∈ A ∧ Y ∈ B → X R Y ∈ R A × B ∪ ∅

Proof

Step Hyp Ref Expression
1 simpr ⊢ X ∈ A ∧ Y ∈ B ∧ X R Y = ∅ → X R Y = ∅
2 ssun2 ⊢ ∅ ⊆ R A × B ∪ ∅
3 0ex ⊢ ∅ ∈ V
4 3 snid ⊢ ∅ ∈ ∅
5 2 4 sselii ⊢ ∅ ∈ R A × B ∪ ∅
6 1 5 eqeltrdi ⊢ X ∈ A ∧ Y ∈ B ∧ X R Y = ∅ → X R Y ∈ R A × B ∪ ∅
7 ssun1 ⊢ R A × B ⊆ R A × B ∪ ∅
8 df-ov ⊢ X R Y = R ⁡ X Y
9 opelxpi ⊢ X ∈ A ∧ Y ∈ B → X Y ∈ A × B
10 8 eqeq1i ⊢ X R Y = ∅ ↔ R ⁡ X Y = ∅
11 10 notbii ⊢ ¬ X R Y = ∅ ↔ ¬ R ⁡ X Y = ∅
12 11 biimpi ⊢ ¬ X R Y = ∅ → ¬ R ⁡ X Y = ∅
13 eliman0 ⊢ X Y ∈ A × B ∧ ¬ R ⁡ X Y = ∅ → R ⁡ X Y ∈ R A × B
14 9 12 13 syl2an ⊢ X ∈ A ∧ Y ∈ B ∧ ¬ X R Y = ∅ → R ⁡ X Y ∈ R A × B
15 8 14 eqeltrid ⊢ X ∈ A ∧ Y ∈ B ∧ ¬ X R Y = ∅ → X R Y ∈ R A × B
16 7 15 sselid ⊢ X ∈ A ∧ Y ∈ B ∧ ¬ X R Y = ∅ → X R Y ∈ R A × B ∪ ∅
17 6 16 pm2.61dan ⊢ X ∈ A ∧ Y ∈ B → X R Y ∈ R A × B ∪ ∅