Metamath Proof Explorer


Theorem pwsring

Description: A structure power of a ring is a ring. (Contributed by Mario Carneiro, 11-Mar-2015)

Ref Expression
Hypothesis pwsring.y ⊢ Y = R ↑ 𝑠 I
Assertion pwsring ⊢ R ∈ Ring ∧ I ∈ V → Y ∈ Ring

Proof

Step Hyp Ref Expression
1 pwsring.y ⊢ Y = R ↑ 𝑠 I
2 eqid ⊢ Scalar ⁡ R = Scalar ⁡ R
3 1 2 pwsval ⊢ R ∈ Ring ∧ I ∈ V → Y = Scalar ⁡ R ⨉ 𝑠 I × R
4 eqid ⊢ Scalar ⁡ R ⨉ 𝑠 I × R = Scalar ⁡ R ⨉ 𝑠 I × R
5 simpr ⊢ R ∈ Ring ∧ I ∈ V → I ∈ V
6 fvexd ⊢ R ∈ Ring ∧ I ∈ V → Scalar ⁡ R ∈ V
7 fconst6g ⊢ R ∈ Ring → I × R : I ⟶ Ring
8 7 adantr ⊢ R ∈ Ring ∧ I ∈ V → I × R : I ⟶ Ring
9 4 5 6 8 prdsringd ⊢ R ∈ Ring ∧ I ∈ V → Scalar ⁡ R ⨉ 𝑠 I × R ∈ Ring
10 3 9 eqeltrd ⊢ R ∈ Ring ∧ I ∈ V → Y ∈ Ring