Metamath Proof Explorer


Theorem r1elwf

Description: Any element of (any stage of) the cumulative hierarchy of sets is well-founded (recall that U. ( R1 " On ) is the class of well-founded sets). (Contributed by Mario Carneiro, 28-May-2013) (Revised by Mario Carneiro, 16-Nov-2014)

Ref Expression
Assertion r1elwf ⊢ A ∈ R1 ⁡ B → A ∈ ⋃ R1 On

Proof

Step Hyp Ref Expression
1 r1dmlim ⊢ Lim ⁡ dom ⁡ R1
2 limord ⊢ Lim ⁡ dom ⁡ R1 → Ord ⁡ dom ⁡ R1
3 ordsson ⊢ Ord ⁡ dom ⁡ R1 → dom ⁡ R1 ⊆ On
4 1 2 3 mp2b ⊢ dom ⁡ R1 ⊆ On
5 elfvdm ⊢ A ∈ R1 ⁡ B → B ∈ dom ⁡ R1
6 4 5 sselid ⊢ A ∈ R1 ⁡ B → B ∈ On
7 r1tr ⊢ Tr ⁡ R1 ⁡ B
8 trss ⊢ Tr ⁡ R1 ⁡ B → A ∈ R1 ⁡ B → A ⊆ R1 ⁡ B
9 7 8 ax-mp ⊢ A ∈ R1 ⁡ B → A ⊆ R1 ⁡ B
10 elpwg ⊢ A ∈ R1 ⁡ B → A ∈ 𝒫 R1 ⁡ B ↔ A ⊆ R1 ⁡ B
11 9 10 mpbird ⊢ A ∈ R1 ⁡ B → A ∈ 𝒫 R1 ⁡ B
12 r1sucg ⊢ B ∈ dom ⁡ R1 → R1 ⁡ suc ⁡ B = 𝒫 R1 ⁡ B
13 5 12 syl ⊢ A ∈ R1 ⁡ B → R1 ⁡ suc ⁡ B = 𝒫 R1 ⁡ B
14 11 13 eleqtrrd ⊢ A ∈ R1 ⁡ B → A ∈ R1 ⁡ suc ⁡ B
15 suceq ⊢ x = B → suc ⁡ x = suc ⁡ B
16 15 fveq2d ⊢ x = B → R1 ⁡ suc ⁡ x = R1 ⁡ suc ⁡ B
17 16 eleq2d ⊢ x = B → A ∈ R1 ⁡ suc ⁡ x ↔ A ∈ R1 ⁡ suc ⁡ B
18 17 rspcev ⊢ B ∈ On ∧ A ∈ R1 ⁡ suc ⁡ B → ∃ x ∈ On A ∈ R1 ⁡ suc ⁡ x
19 6 14 18 syl2anc ⊢ A ∈ R1 ⁡ B → ∃ x ∈ On A ∈ R1 ⁡ suc ⁡ x
20 rankwflemb ⊢ A ∈ ⋃ R1 On ↔ ∃ x ∈ On A ∈ R1 ⁡ suc ⁡ x
21 19 20 sylibr ⊢ A ∈ R1 ⁡ B → A ∈ ⋃ R1 On