Metamath Proof Explorer


Theorem r1elwf

Description: Any element of (any stage of) the cumulative hierarchy of sets is well-founded (recall that U. ( R1 " On ) is the class of well-founded sets). (Contributed by Mario Carneiro, 28-May-2013) (Revised by Mario Carneiro, 16-Nov-2014)

Ref Expression
Assertion r1elwf
|- ( A e. ( R1 ` B ) -> A e. U. ( R1 " On ) )

Proof

Step Hyp Ref Expression
1 r1dmlim
 |-  Lim dom R1
2 limord
 |-  ( Lim dom R1 -> Ord dom R1 )
3 ordsson
 |-  ( Ord dom R1 -> dom R1 C_ On )
4 1 2 3 mp2b
 |-  dom R1 C_ On
5 elfvdm
 |-  ( A e. ( R1 ` B ) -> B e. dom R1 )
6 4 5 sselid
 |-  ( A e. ( R1 ` B ) -> B e. On )
7 r1tr
 |-  Tr ( R1 ` B )
8 trss
 |-  ( Tr ( R1 ` B ) -> ( A e. ( R1 ` B ) -> A C_ ( R1 ` B ) ) )
9 7 8 ax-mp
 |-  ( A e. ( R1 ` B ) -> A C_ ( R1 ` B ) )
10 elpwg
 |-  ( A e. ( R1 ` B ) -> ( A e. ~P ( R1 ` B ) <-> A C_ ( R1 ` B ) ) )
11 9 10 mpbird
 |-  ( A e. ( R1 ` B ) -> A e. ~P ( R1 ` B ) )
12 r1sucg
 |-  ( B e. dom R1 -> ( R1 ` suc B ) = ~P ( R1 ` B ) )
13 5 12 syl
 |-  ( A e. ( R1 ` B ) -> ( R1 ` suc B ) = ~P ( R1 ` B ) )
14 11 13 eleqtrrd
 |-  ( A e. ( R1 ` B ) -> A e. ( R1 ` suc B ) )
15 suceq
 |-  ( x = B -> suc x = suc B )
16 15 fveq2d
 |-  ( x = B -> ( R1 ` suc x ) = ( R1 ` suc B ) )
17 16 eleq2d
 |-  ( x = B -> ( A e. ( R1 ` suc x ) <-> A e. ( R1 ` suc B ) ) )
18 17 rspcev
 |-  ( ( B e. On /\ A e. ( R1 ` suc B ) ) -> E. x e. On A e. ( R1 ` suc x ) )
19 6 14 18 syl2anc
 |-  ( A e. ( R1 ` B ) -> E. x e. On A e. ( R1 ` suc x ) )
20 rankwflemb
 |-  ( A e. U. ( R1 " On ) <-> E. x e. On A e. ( R1 ` suc x ) )
21 19 20 sylibr
 |-  ( A e. ( R1 ` B ) -> A e. U. ( R1 " On ) )