Metamath Proof Explorer


Theorem r1ord3g

Description: Ordering relation for the cumulative hierarchy of sets. Part of Theorem 3.3(i) of BellMachover p. 478. (Contributed by NM, 22-Sep-2003)

Ref Expression
Assertion r1ord3g ⊢ A ∈ dom ⁡ R1 ∧ B ∈ dom ⁡ R1 → A ⊆ B → R1 ⁡ A ⊆ R1 ⁡ B

Proof

Step Hyp Ref Expression
1 r1dmlim ⊢ Lim ⁡ dom ⁡ R1
2 limord ⊢ Lim ⁡ dom ⁡ R1 → Ord ⁡ dom ⁡ R1
3 ordsson ⊢ Ord ⁡ dom ⁡ R1 → dom ⁡ R1 ⊆ On
4 1 2 3 mp2b ⊢ dom ⁡ R1 ⊆ On
5 4 sseli ⊢ A ∈ dom ⁡ R1 → A ∈ On
6 4 sseli ⊢ B ∈ dom ⁡ R1 → B ∈ On
7 onsseleq ⊢ A ∈ On ∧ B ∈ On → A ⊆ B ↔ A ∈ B ∨ A = B
8 5 6 7 syl2an ⊢ A ∈ dom ⁡ R1 ∧ B ∈ dom ⁡ R1 → A ⊆ B ↔ A ∈ B ∨ A = B
9 r1tr ⊢ Tr ⁡ R1 ⁡ B
10 r1ordg ⊢ B ∈ dom ⁡ R1 → A ∈ B → R1 ⁡ A ∈ R1 ⁡ B
11 10 adantl ⊢ A ∈ dom ⁡ R1 ∧ B ∈ dom ⁡ R1 → A ∈ B → R1 ⁡ A ∈ R1 ⁡ B
12 trss ⊢ Tr ⁡ R1 ⁡ B → R1 ⁡ A ∈ R1 ⁡ B → R1 ⁡ A ⊆ R1 ⁡ B
13 9 11 12 mpsylsyld ⊢ A ∈ dom ⁡ R1 ∧ B ∈ dom ⁡ R1 → A ∈ B → R1 ⁡ A ⊆ R1 ⁡ B
14 fveq2 ⊢ A = B → R1 ⁡ A = R1 ⁡ B
15 eqimss ⊢ R1 ⁡ A = R1 ⁡ B → R1 ⁡ A ⊆ R1 ⁡ B
16 14 15 syl ⊢ A = B → R1 ⁡ A ⊆ R1 ⁡ B
17 16 a1i ⊢ A ∈ dom ⁡ R1 ∧ B ∈ dom ⁡ R1 → A = B → R1 ⁡ A ⊆ R1 ⁡ B
18 13 17 jaod ⊢ A ∈ dom ⁡ R1 ∧ B ∈ dom ⁡ R1 → A ∈ B ∨ A = B → R1 ⁡ A ⊆ R1 ⁡ B
19 8 18 sylbid ⊢ A ∈ dom ⁡ R1 ∧ B ∈ dom ⁡ R1 → A ⊆ B → R1 ⁡ A ⊆ R1 ⁡ B