Metamath Proof Explorer


Theorem reprfz1

Description: Corollary of reprinfz1 . (Contributed by Thierry Arnoux, 14-Dec-2021)

Ref Expression
Hypotheses reprfz1.n ⊢ φ → N ∈ ℕ 0
reprfz1.s ⊢ φ → S ∈ ℕ 0
Assertion reprfz1 ⊢ φ → ℕ repr ⁡ S N = 1 … N repr ⁡ S N

Proof

Step Hyp Ref Expression
1 reprfz1.n ⊢ φ → N ∈ ℕ 0
2 reprfz1.s ⊢ φ → S ∈ ℕ 0
3 ssidd ⊢ φ → ℕ ⊆ ℕ
4 1 2 3 reprinfz1 ⊢ φ → ℕ repr ⁡ S N = ℕ ∩ 1 … N repr ⁡ S N
5 fz1ssnn ⊢ 1 … N ⊆ ℕ
6 dfss ⊢ 1 … N ⊆ ℕ ↔ 1 … N = 1 … N ∩ ℕ
7 5 6 mpbi ⊢ 1 … N = 1 … N ∩ ℕ
8 incom ⊢ 1 … N ∩ ℕ = ℕ ∩ 1 … N
9 7 8 eqtri ⊢ 1 … N = ℕ ∩ 1 … N
10 9 oveq1i ⊢ 1 … N repr ⁡ S N = ℕ ∩ 1 … N repr ⁡ S N
11 4 10 eqtr4di ⊢ φ → ℕ repr ⁡ S N = 1 … N repr ⁡ S N