Metamath Proof Explorer


Theorem resqrtvalex

Description: Example for resqrtval . (Contributed by RP, 21-May-2024)

Ref Expression
Assertion resqrtvalex ⊢ ℜ ⁡ 15 + i ⋅ 8 = 4

Proof

Step Hyp Ref Expression
1 1nn0 ⊢ 1 ∈ ℕ 0
2 5nn0 ⊢ 5 ∈ ℕ 0
3 1 2 deccl ⊢ 15 ∈ ℕ 0
4 3 nn0cni ⊢ 15 ∈ ℂ
5 ax-icn ⊢ i ∈ ℂ
6 8cn ⊢ 8 ∈ ℂ
7 5 6 mulcli ⊢ i ⋅ 8 ∈ ℂ
8 4 7 addcli ⊢ 15 + i ⋅ 8 ∈ ℂ
9 resqrtval ⊢ 15 + i ⋅ 8 ∈ ℂ → ℜ ⁡ 15 + i ⋅ 8 = 15 + i ⋅ 8 + ℜ ⁡ 15 + i ⋅ 8 2
10 8 9 ax-mp ⊢ ℜ ⁡ 15 + i ⋅ 8 = 15 + i ⋅ 8 + ℜ ⁡ 15 + i ⋅ 8 2
11 7nn0 ⊢ 7 ∈ ℕ 0
12 3 nn0rei ⊢ 15 ∈ ℝ
13 8re ⊢ 8 ∈ ℝ
14 absreim ⊢ 15 ∈ ℝ ∧ 8 ∈ ℝ → 15 + i ⋅ 8 = 15 2 + 8 2
15 12 13 14 mp2an ⊢ 15 + i ⋅ 8 = 15 2 + 8 2
16 4 sqvali ⊢ 15 2 = 15 ⋅ 15
17 eqid ⊢ 15 = 15
18 4 mullidi ⊢ 1 ⋅ 15 = 15
19 1p1e2 ⊢ 1 + 1 = 2
20 2nn0 ⊢ 2 ∈ ℕ 0
21 11 nn0cni ⊢ 7 ∈ ℂ
22 2 nn0cni ⊢ 5 ∈ ℂ
23 7p5e12 ⊢ 7 + 5 = 12
24 21 22 23 addcomli ⊢ 5 + 7 = 12
25 1 2 11 18 19 20 24 decaddci ⊢ 1 ⋅ 15 + 7 = 22
26 22 mulridi ⊢ 5 ⋅ 1 = 5
27 26 oveq1i ⊢ 5 ⋅ 1 + 2 = 5 + 2
28 5p2e7 ⊢ 5 + 2 = 7
29 27 28 eqtri ⊢ 5 ⋅ 1 + 2 = 7
30 5t5e25 ⊢ 5 ⋅ 5 = 25
31 2 1 2 17 2 20 29 30 decmul2c ⊢ 5 ⋅ 15 = 75
32 3 1 2 17 2 11 25 31 decmul1c ⊢ 15 ⋅ 15 = 225
33 16 32 eqtri ⊢ 15 2 = 225
34 6 sqvali ⊢ 8 2 = 8 ⋅ 8
35 8t8e64 ⊢ 8 ⋅ 8 = 64
36 34 35 eqtri ⊢ 8 2 = 64
37 33 36 oveq12i ⊢ 15 2 + 8 2 = 225 + 64
38 20 20 deccl ⊢ 22 ∈ ℕ 0
39 6nn0 ⊢ 6 ∈ ℕ 0
40 4nn0 ⊢ 4 ∈ ℕ 0
41 eqid ⊢ 225 = 225
42 eqid ⊢ 64 = 64
43 eqid ⊢ 22 = 22
44 39 nn0cni ⊢ 6 ∈ ℂ
45 2cn ⊢ 2 ∈ ℂ
46 6p2e8 ⊢ 6 + 2 = 8
47 44 45 46 addcomli ⊢ 2 + 6 = 8
48 20 20 39 43 47 decaddi ⊢ 22 + 6 = 28
49 5p4e9 ⊢ 5 + 4 = 9
50 38 2 39 40 41 42 48 49 decadd ⊢ 225 + 64 = 289
51 1 11 deccl ⊢ 17 ∈ ℕ 0
52 51 nn0cni ⊢ 17 ∈ ℂ
53 52 sqvali ⊢ 17 2 = 17 ⋅ 17
54 eqid ⊢ 17 = 17
55 9nn0 ⊢ 9 ∈ ℕ 0
56 1 1 deccl ⊢ 11 ∈ ℕ 0
57 52 mullidi ⊢ 1 ⋅ 17 = 17
58 eqid ⊢ 11 = 11
59 7p1e8 ⊢ 7 + 1 = 8
60 1 11 1 1 57 58 19 59 decadd ⊢ 1 ⋅ 17 + 11 = 28
61 21 mulridi ⊢ 7 ⋅ 1 = 7
62 61 oveq1i ⊢ 7 ⋅ 1 + 4 = 7 + 4
63 7p4e11 ⊢ 7 + 4 = 11
64 62 63 eqtri ⊢ 7 ⋅ 1 + 4 = 11
65 7t7e49 ⊢ 7 ⋅ 7 = 49
66 11 1 11 54 55 40 64 65 decmul2c ⊢ 7 ⋅ 17 = 119
67 51 1 11 54 55 56 60 66 decmul1c ⊢ 17 ⋅ 17 = 289
68 53 67 eqtr2i ⊢ 289 = 17 2
69 37 50 68 3eqtri ⊢ 15 2 + 8 2 = 17 2
70 69 fveq2i ⊢ 15 2 + 8 2 = 17 2
71 51 nn0ge0i ⊢ 0 ≤ 17
72 51 nn0rei ⊢ 17 ∈ ℝ
73 72 sqrtsqi ⊢ 0 ≤ 17 → 17 2 = 17
74 71 73 ax-mp ⊢ 17 2 = 17
75 15 70 74 3eqtri ⊢ 15 + i ⋅ 8 = 17
76 12 13 crrei ⊢ ℜ ⁡ 15 + i ⋅ 8 = 15
77 19 oveq1i ⊢ 1 + 1 + 1 = 2 + 1
78 2p1e3 ⊢ 2 + 1 = 3
79 77 78 eqtri ⊢ 1 + 1 + 1 = 3
80 1 11 1 2 75 76 79 20 23 decaddc ⊢ 15 + i ⋅ 8 + ℜ ⁡ 15 + i ⋅ 8 = 32
81 80 oveq1i ⊢ 15 + i ⋅ 8 + ℜ ⁡ 15 + i ⋅ 8 2 = 32 2
82 eqid ⊢ 16 = 16
83 45 mulridi ⊢ 2 ⋅ 1 = 2
84 83 oveq1i ⊢ 2 ⋅ 1 + 1 = 2 + 1
85 84 78 eqtri ⊢ 2 ⋅ 1 + 1 = 3
86 6t2e12 ⊢ 6 ⋅ 2 = 12
87 44 45 86 mulcomli ⊢ 2 ⋅ 6 = 12
88 20 1 39 82 20 1 85 87 decmul2c ⊢ 2 ⋅ 16 = 32
89 3nn0 ⊢ 3 ∈ ℕ 0
90 89 20 deccl ⊢ 32 ∈ ℕ 0
91 90 nn0cni ⊢ 32 ∈ ℂ
92 1 39 deccl ⊢ 16 ∈ ℕ 0
93 92 nn0cni ⊢ 16 ∈ ℂ
94 2ne0 ⊢ 2 ≠ 0
95 91 45 93 94 divmuli ⊢ 32 2 = 16 ↔ 2 ⋅ 16 = 32
96 88 95 mpbir ⊢ 32 2 = 16
97 40 nn0cni ⊢ 4 ∈ ℂ
98 97 sqvali ⊢ 4 2 = 4 ⋅ 4
99 4t4e16 ⊢ 4 ⋅ 4 = 16
100 98 99 eqtr2i ⊢ 16 = 4 2
101 81 96 100 3eqtri ⊢ 15 + i ⋅ 8 + ℜ ⁡ 15 + i ⋅ 8 2 = 4 2
102 101 fveq2i ⊢ 15 + i ⋅ 8 + ℜ ⁡ 15 + i ⋅ 8 2 = 4 2
103 40 nn0ge0i ⊢ 0 ≤ 4
104 40 nn0rei ⊢ 4 ∈ ℝ
105 104 sqrtsqi ⊢ 0 ≤ 4 → 4 2 = 4
106 103 105 ax-mp ⊢ 4 2 = 4
107 10 102 106 3eqtri ⊢ ℜ ⁡ 15 + i ⋅ 8 = 4