Metamath Proof Explorer


Theorem rngisomfv1

Description: If there is a non-unital ring isomorphism between a unital ring and a non-unital ring, then the function value of the ring unity of the unital ring is an element of the base set of the non-unital ring. (Contributed by AV, 27-Feb-2025)

Ref Expression
Hypotheses rngisom1.1 ⊢ 1 ˙ = 1 R
rngisom1.b ⊢ B = Base S
Assertion rngisomfv1 ⊢ R ∈ Ring ∧ F ∈ R RngIso S → F ⁡ 1 ˙ ∈ B

Proof

Step Hyp Ref Expression
1 rngisom1.1 ⊢ 1 ˙ = 1 R
2 rngisom1.b ⊢ B = Base S
3 eqid ⊢ Base R = Base R
4 3 2 rngimf1o ⊢ F ∈ R RngIso S → F : Base R ⟶ 1-1 onto B
5 f1of ⊢ F : Base R ⟶ 1-1 onto B → F : Base R ⟶ B
6 4 5 syl ⊢ F ∈ R RngIso S → F : Base R ⟶ B
7 6 adantl ⊢ R ∈ Ring ∧ F ∈ R RngIso S → F : Base R ⟶ B
8 3 1 ringidcl ⊢ R ∈ Ring → 1 ˙ ∈ Base R
9 8 adantr ⊢ R ∈ Ring ∧ F ∈ R RngIso S → 1 ˙ ∈ Base R
10 7 9 ffvelcdmd ⊢ R ∈ Ring ∧ F ∈ R RngIso S → F ⁡ 1 ˙ ∈ B