Metamath Proof Explorer


Theorem rrgeq0

Description: Left-multiplication by a left regular element does not change zeroness. (Contributed by Stefan O'Rear, 28-Mar-2015)

Ref Expression
Hypotheses rrgval.e ⊢ E = RLReg ⁡ R
rrgval.b ⊢ B = Base R
rrgval.t ⊢ · ˙ = ⋅ R
rrgval.z ⊢ 0 ˙ = 0 R
Assertion rrgeq0 ⊢ R ∈ Ring ∧ X ∈ E ∧ Y ∈ B → X · ˙ Y = 0 ˙ ↔ Y = 0 ˙

Proof

Step Hyp Ref Expression
1 rrgval.e ⊢ E = RLReg ⁡ R
2 rrgval.b ⊢ B = Base R
3 rrgval.t ⊢ · ˙ = ⋅ R
4 rrgval.z ⊢ 0 ˙ = 0 R
5 1 2 3 4 rrgeq0i ⊢ X ∈ E ∧ Y ∈ B → X · ˙ Y = 0 ˙ → Y = 0 ˙
6 5 3adant1 ⊢ R ∈ Ring ∧ X ∈ E ∧ Y ∈ B → X · ˙ Y = 0 ˙ → Y = 0 ˙
7 simp1 ⊢ R ∈ Ring ∧ X ∈ E ∧ Y ∈ B → R ∈ Ring
8 1 2 3 4 rrgval ⊢ E = x ∈ B | ∀ y ∈ B x · ˙ y = 0 ˙ → y = 0 ˙
9 8 ssrab3 ⊢ E ⊆ B
10 simp2 ⊢ R ∈ Ring ∧ X ∈ E ∧ Y ∈ B → X ∈ E
11 9 10 sselid ⊢ R ∈ Ring ∧ X ∈ E ∧ Y ∈ B → X ∈ B
12 2 3 4 ringrz ⊢ R ∈ Ring ∧ X ∈ B → X · ˙ 0 ˙ = 0 ˙
13 7 11 12 syl2anc ⊢ R ∈ Ring ∧ X ∈ E ∧ Y ∈ B → X · ˙ 0 ˙ = 0 ˙
14 oveq2 ⊢ Y = 0 ˙ → X · ˙ Y = X · ˙ 0 ˙
15 14 eqeq1d ⊢ Y = 0 ˙ → X · ˙ Y = 0 ˙ ↔ X · ˙ 0 ˙ = 0 ˙
16 13 15 syl5ibrcom ⊢ R ∈ Ring ∧ X ∈ E ∧ Y ∈ B → Y = 0 ˙ → X · ˙ Y = 0 ˙
17 6 16 impbid ⊢ R ∈ Ring ∧ X ∈ E ∧ Y ∈ B → X · ˙ Y = 0 ˙ ↔ Y = 0 ˙