Metamath Proof Explorer


Theorem sbthlem1

Description: Lemma for sbth . (Contributed by NM, 22-Mar-1998)

Ref Expression
Hypotheses sbthlem.1 ⊢ A ∈ V
sbthlem.2 ⊢ D = x | x ⊆ A ∧ g B ∖ f x ⊆ A ∖ x
Assertion sbthlem1 ⊢ ⋃ D ⊆ A ∖ g B ∖ f ⋃ D

Proof

Step Hyp Ref Expression
1 sbthlem.1 ⊢ A ∈ V
2 sbthlem.2 ⊢ D = x | x ⊆ A ∧ g B ∖ f x ⊆ A ∖ x
3 unissb ⊢ ⋃ D ⊆ A ∖ g B ∖ f ⋃ D ↔ ∀ x ∈ D x ⊆ A ∖ g B ∖ f ⋃ D
4 2 eqabri ⊢ x ∈ D ↔ x ⊆ A ∧ g B ∖ f x ⊆ A ∖ x
5 difss2 ⊢ g B ∖ f x ⊆ A ∖ x → g B ∖ f x ⊆ A
6 ssconb ⊢ x ⊆ A ∧ g B ∖ f x ⊆ A → x ⊆ A ∖ g B ∖ f x ↔ g B ∖ f x ⊆ A ∖ x
7 6 exbiri ⊢ x ⊆ A → g B ∖ f x ⊆ A → g B ∖ f x ⊆ A ∖ x → x ⊆ A ∖ g B ∖ f x
8 5 7 syl5 ⊢ x ⊆ A → g B ∖ f x ⊆ A ∖ x → g B ∖ f x ⊆ A ∖ x → x ⊆ A ∖ g B ∖ f x
9 8 pm2.43d ⊢ x ⊆ A → g B ∖ f x ⊆ A ∖ x → x ⊆ A ∖ g B ∖ f x
10 9 imp ⊢ x ⊆ A ∧ g B ∖ f x ⊆ A ∖ x → x ⊆ A ∖ g B ∖ f x
11 4 10 sylbi ⊢ x ∈ D → x ⊆ A ∖ g B ∖ f x
12 elssuni ⊢ x ∈ D → x ⊆ ⋃ D
13 imass2 ⊢ x ⊆ ⋃ D → f x ⊆ f ⋃ D
14 sscon ⊢ f x ⊆ f ⋃ D → B ∖ f ⋃ D ⊆ B ∖ f x
15 12 13 14 3syl ⊢ x ∈ D → B ∖ f ⋃ D ⊆ B ∖ f x
16 imass2 ⊢ B ∖ f ⋃ D ⊆ B ∖ f x → g B ∖ f ⋃ D ⊆ g B ∖ f x
17 sscon ⊢ g B ∖ f ⋃ D ⊆ g B ∖ f x → A ∖ g B ∖ f x ⊆ A ∖ g B ∖ f ⋃ D
18 15 16 17 3syl ⊢ x ∈ D → A ∖ g B ∖ f x ⊆ A ∖ g B ∖ f ⋃ D
19 11 18 sstrd ⊢ x ∈ D → x ⊆ A ∖ g B ∖ f ⋃ D
20 3 19 mprgbir ⊢ ⋃ D ⊆ A ∖ g B ∖ f ⋃ D