Metamath Proof Explorer


Theorem sbthlem2

Description: Lemma for sbth . (Contributed by NM, 22-Mar-1998)

Ref Expression
Hypotheses sbthlem.1 ⊢ A ∈ V
sbthlem.2 ⊢ D = x | x ⊆ A ∧ g B ∖ f x ⊆ A ∖ x
Assertion sbthlem2 ⊢ ran ⁡ g ⊆ A → A ∖ g B ∖ f ⋃ D ⊆ ⋃ D

Proof

Step Hyp Ref Expression
1 sbthlem.1 ⊢ A ∈ V
2 sbthlem.2 ⊢ D = x | x ⊆ A ∧ g B ∖ f x ⊆ A ∖ x
3 1 2 sbthlem1 ⊢ ⋃ D ⊆ A ∖ g B ∖ f ⋃ D
4 imass2 ⊢ ⋃ D ⊆ A ∖ g B ∖ f ⋃ D → f ⋃ D ⊆ f A ∖ g B ∖ f ⋃ D
5 sscon ⊢ f ⋃ D ⊆ f A ∖ g B ∖ f ⋃ D → B ∖ f A ∖ g B ∖ f ⋃ D ⊆ B ∖ f ⋃ D
6 3 4 5 mp2b ⊢ B ∖ f A ∖ g B ∖ f ⋃ D ⊆ B ∖ f ⋃ D
7 imass2 ⊢ B ∖ f A ∖ g B ∖ f ⋃ D ⊆ B ∖ f ⋃ D → g B ∖ f A ∖ g B ∖ f ⋃ D ⊆ g B ∖ f ⋃ D
8 sscon ⊢ g B ∖ f A ∖ g B ∖ f ⋃ D ⊆ g B ∖ f ⋃ D → A ∖ g B ∖ f ⋃ D ⊆ A ∖ g B ∖ f A ∖ g B ∖ f ⋃ D
9 6 7 8 mp2b ⊢ A ∖ g B ∖ f ⋃ D ⊆ A ∖ g B ∖ f A ∖ g B ∖ f ⋃ D
10 imassrn ⊢ g B ∖ f A ∖ g B ∖ f ⋃ D ⊆ ran ⁡ g
11 sstr2 ⊢ g B ∖ f A ∖ g B ∖ f ⋃ D ⊆ ran ⁡ g → ran ⁡ g ⊆ A → g B ∖ f A ∖ g B ∖ f ⋃ D ⊆ A
12 10 11 ax-mp ⊢ ran ⁡ g ⊆ A → g B ∖ f A ∖ g B ∖ f ⋃ D ⊆ A
13 difss ⊢ A ∖ g B ∖ f ⋃ D ⊆ A
14 ssconb ⊢ g B ∖ f A ∖ g B ∖ f ⋃ D ⊆ A ∧ A ∖ g B ∖ f ⋃ D ⊆ A → g B ∖ f A ∖ g B ∖ f ⋃ D ⊆ A ∖ A ∖ g B ∖ f ⋃ D ↔ A ∖ g B ∖ f ⋃ D ⊆ A ∖ g B ∖ f A ∖ g B ∖ f ⋃ D
15 12 13 14 sylancl ⊢ ran ⁡ g ⊆ A → g B ∖ f A ∖ g B ∖ f ⋃ D ⊆ A ∖ A ∖ g B ∖ f ⋃ D ↔ A ∖ g B ∖ f ⋃ D ⊆ A ∖ g B ∖ f A ∖ g B ∖ f ⋃ D
16 9 15 mpbiri ⊢ ran ⁡ g ⊆ A → g B ∖ f A ∖ g B ∖ f ⋃ D ⊆ A ∖ A ∖ g B ∖ f ⋃ D
17 16 13 jctil ⊢ ran ⁡ g ⊆ A → A ∖ g B ∖ f ⋃ D ⊆ A ∧ g B ∖ f A ∖ g B ∖ f ⋃ D ⊆ A ∖ A ∖ g B ∖ f ⋃ D
18 1 difexi ⊢ A ∖ g B ∖ f ⋃ D ∈ V
19 sseq1 ⊢ x = A ∖ g B ∖ f ⋃ D → x ⊆ A ↔ A ∖ g B ∖ f ⋃ D ⊆ A
20 imaeq2 ⊢ x = A ∖ g B ∖ f ⋃ D → f x = f A ∖ g B ∖ f ⋃ D
21 20 difeq2d ⊢ x = A ∖ g B ∖ f ⋃ D → B ∖ f x = B ∖ f A ∖ g B ∖ f ⋃ D
22 21 imaeq2d ⊢ x = A ∖ g B ∖ f ⋃ D → g B ∖ f x = g B ∖ f A ∖ g B ∖ f ⋃ D
23 difeq2 ⊢ x = A ∖ g B ∖ f ⋃ D → A ∖ x = A ∖ A ∖ g B ∖ f ⋃ D
24 22 23 sseq12d ⊢ x = A ∖ g B ∖ f ⋃ D → g B ∖ f x ⊆ A ∖ x ↔ g B ∖ f A ∖ g B ∖ f ⋃ D ⊆ A ∖ A ∖ g B ∖ f ⋃ D
25 19 24 anbi12d ⊢ x = A ∖ g B ∖ f ⋃ D → x ⊆ A ∧ g B ∖ f x ⊆ A ∖ x ↔ A ∖ g B ∖ f ⋃ D ⊆ A ∧ g B ∖ f A ∖ g B ∖ f ⋃ D ⊆ A ∖ A ∖ g B ∖ f ⋃ D
26 18 25 elab ⊢ A ∖ g B ∖ f ⋃ D ∈ x | x ⊆ A ∧ g B ∖ f x ⊆ A ∖ x ↔ A ∖ g B ∖ f ⋃ D ⊆ A ∧ g B ∖ f A ∖ g B ∖ f ⋃ D ⊆ A ∖ A ∖ g B ∖ f ⋃ D
27 17 26 sylibr ⊢ ran ⁡ g ⊆ A → A ∖ g B ∖ f ⋃ D ∈ x | x ⊆ A ∧ g B ∖ f x ⊆ A ∖ x
28 27 2 eleqtrrdi ⊢ ran ⁡ g ⊆ A → A ∖ g B ∖ f ⋃ D ∈ D
29 elssuni ⊢ A ∖ g B ∖ f ⋃ D ∈ D → A ∖ g B ∖ f ⋃ D ⊆ ⋃ D
30 28 29 syl ⊢ ran ⁡ g ⊆ A → A ∖ g B ∖ f ⋃ D ⊆ ⋃ D