Metamath Proof Explorer


Theorem signstfveq0a

Description: Lemma for signstfveq0 . (Contributed by Thierry Arnoux, 11-Oct-2018)

Ref Expression
Hypotheses signsv.p ⊢ ⨣ ˙ = a ∈ − 1 0 1 , b ∈ − 1 0 1 ⟼ if b = 0 a b
signsv.w ⊢ W = Base ndx − 1 0 1 + ndx ⨣ ˙
signsv.t ⊢ T = f ∈ Word ℝ ⟼ n ∈ 0 ..^ f ⟼ ∑ W i = 0 n sgn ⁡ f ⁡ i
signsv.v ⊢ V = f ∈ Word ℝ ⟼ ∑ j ∈ 1 ..^ f if T ⁡ f ⁡ j ≠ T ⁡ f ⁡ j − 1 1 0
signstfveq0.1 ⊢ N = F
Assertion signstfveq0a ⊢ F ∈ Word ℝ ∖ ∅ ∧ F ⁡ 0 ≠ 0 ∧ F ⁡ N − 1 = 0 → N ∈ ℤ ≥ 2

Proof

Step Hyp Ref Expression
1 signsv.p ⊢ ⨣ ˙ = a ∈ − 1 0 1 , b ∈ − 1 0 1 ⟼ if b = 0 a b
2 signsv.w ⊢ W = Base ndx − 1 0 1 + ndx ⨣ ˙
3 signsv.t ⊢ T = f ∈ Word ℝ ⟼ n ∈ 0 ..^ f ⟼ ∑ W i = 0 n sgn ⁡ f ⁡ i
4 signsv.v ⊢ V = f ∈ Word ℝ ⟼ ∑ j ∈ 1 ..^ f if T ⁡ f ⁡ j ≠ T ⁡ f ⁡ j − 1 1 0
5 signstfveq0.1 ⊢ N = F
6 simpll ⊢ F ∈ Word ℝ ∖ ∅ ∧ F ⁡ 0 ≠ 0 ∧ F ⁡ N − 1 = 0 → F ∈ Word ℝ ∖ ∅
7 6 eldifad ⊢ F ∈ Word ℝ ∖ ∅ ∧ F ⁡ 0 ≠ 0 ∧ F ⁡ N − 1 = 0 → F ∈ Word ℝ
8 lencl ⊢ F ∈ Word ℝ → F ∈ ℕ 0
9 5 8 eqeltrid ⊢ F ∈ Word ℝ → N ∈ ℕ 0
10 7 9 syl ⊢ F ∈ Word ℝ ∖ ∅ ∧ F ⁡ 0 ≠ 0 ∧ F ⁡ N − 1 = 0 → N ∈ ℕ 0
11 eldifsn ⊢ F ∈ Word ℝ ∖ ∅ ↔ F ∈ Word ℝ ∧ F ≠ ∅
12 6 11 sylib ⊢ F ∈ Word ℝ ∖ ∅ ∧ F ⁡ 0 ≠ 0 ∧ F ⁡ N − 1 = 0 → F ∈ Word ℝ ∧ F ≠ ∅
13 hasheq0 ⊢ F ∈ Word ℝ → F = 0 ↔ F = ∅
14 13 necon3bid ⊢ F ∈ Word ℝ → F ≠ 0 ↔ F ≠ ∅
15 14 biimpar ⊢ F ∈ Word ℝ ∧ F ≠ ∅ → F ≠ 0
16 5 neeq1i ⊢ N ≠ 0 ↔ F ≠ 0
17 15 16 sylibr ⊢ F ∈ Word ℝ ∧ F ≠ ∅ → N ≠ 0
18 12 17 syl ⊢ F ∈ Word ℝ ∖ ∅ ∧ F ⁡ 0 ≠ 0 ∧ F ⁡ N − 1 = 0 → N ≠ 0
19 elnnne0 ⊢ N ∈ ℕ ↔ N ∈ ℕ 0 ∧ N ≠ 0
20 10 18 19 sylanbrc ⊢ F ∈ Word ℝ ∖ ∅ ∧ F ⁡ 0 ≠ 0 ∧ F ⁡ N − 1 = 0 → N ∈ ℕ
21 simplr ⊢ F ∈ Word ℝ ∖ ∅ ∧ F ⁡ 0 ≠ 0 ∧ F ⁡ N − 1 = 0 → F ⁡ 0 ≠ 0
22 simpr ⊢ F ∈ Word ℝ ∖ ∅ ∧ F ⁡ 0 ≠ 0 ∧ F ⁡ N − 1 = 0 → F ⁡ N − 1 = 0
23 21 22 neeqtrrd ⊢ F ∈ Word ℝ ∖ ∅ ∧ F ⁡ 0 ≠ 0 ∧ F ⁡ N − 1 = 0 → F ⁡ 0 ≠ F ⁡ N − 1
24 23 necomd ⊢ F ∈ Word ℝ ∖ ∅ ∧ F ⁡ 0 ≠ 0 ∧ F ⁡ N − 1 = 0 → F ⁡ N − 1 ≠ F ⁡ 0
25 oveq1 ⊢ N = 1 → N − 1 = 1 − 1
26 1m1e0 ⊢ 1 − 1 = 0
27 25 26 eqtrdi ⊢ N = 1 → N − 1 = 0
28 27 fveq2d ⊢ N = 1 → F ⁡ N − 1 = F ⁡ 0
29 28 necon3i ⊢ F ⁡ N − 1 ≠ F ⁡ 0 → N ≠ 1
30 24 29 syl ⊢ F ∈ Word ℝ ∖ ∅ ∧ F ⁡ 0 ≠ 0 ∧ F ⁡ N − 1 = 0 → N ≠ 1
31 eluz2b3 ⊢ N ∈ ℤ ≥ 2 ↔ N ∈ ℕ ∧ N ≠ 1
32 20 30 31 sylanbrc ⊢ F ∈ Word ℝ ∖ ∅ ∧ F ⁡ 0 ≠ 0 ∧ F ⁡ N − 1 = 0 → N ∈ ℤ ≥ 2