Metamath Proof Explorer


Theorem slesubd

Description: Swap subtrahends in a surreal inequality. (Contributed by Scott Fenton, 29-Jan-2026)

Ref Expression
Hypotheses slesubd.1 φ A No
slesubd.2 φ B No
slesubd.3 φ C No
Assertion slesubd φ A s B - s C C s B - s A

Proof

Step Hyp Ref Expression
1 slesubd.1 φ A No
2 slesubd.2 φ B No
3 slesubd.3 φ C No
4 npcans B No A No B - s A + s A = B
5 2 1 4 syl2anc φ B - s A + s A = B
6 2 1 subscld φ B - s A No
7 1 6 addscomd φ A + s B - s A = B - s A + s A
8 npcans B No C No B - s C + s C = B
9 2 3 8 syl2anc φ B - s C + s C = B
10 5 7 9 3eqtr4rd φ B - s C + s C = A + s B - s A
11 10 breq2d φ A + s C s B - s C + s C A + s C s A + s B - s A
12 2 3 subscld φ B - s C No
13 1 12 3 sleadd1d φ A s B - s C A + s C s B - s C + s C
14 3 6 1 sleadd2d φ C s B - s A A + s C s A + s B - s A
15 11 13 14 3bitr4d φ A s B - s C C s B - s A