Metamath Proof Explorer


Theorem smueq

Description: Any element of a sequence multiplication only depends on the values of the argument sequences up to and including that point. (Contributed by Mario Carneiro, 20-Sep-2016)

Ref Expression
Hypotheses smueq.a ⊢ φ → A ⊆ ℕ 0
smueq.b ⊢ φ → B ⊆ ℕ 0
smueq.n ⊢ φ → N ∈ ℕ 0
Assertion smueq ⊢ φ → A smul B ∩ 0 ..^ N = A ∩ 0 ..^ N smul B ∩ 0 ..^ N ∩ 0 ..^ N

Proof

Step Hyp Ref Expression
1 smueq.a ⊢ φ → A ⊆ ℕ 0
2 smueq.b ⊢ φ → B ⊆ ℕ 0
3 smueq.n ⊢ φ → N ∈ ℕ 0
4 eqid ⊢ seq 0 p ∈ 𝒫 ℕ 0 , m ∈ ℕ 0 ⟼ p sadd n ∈ ℕ 0 | m ∈ A ∧ n − m ∈ B n ∈ ℕ 0 ⟼ if n = 0 ∅ n − 1 = seq 0 p ∈ 𝒫 ℕ 0 , m ∈ ℕ 0 ⟼ p sadd n ∈ ℕ 0 | m ∈ A ∧ n − m ∈ B n ∈ ℕ 0 ⟼ if n = 0 ∅ n − 1
5 eqid ⊢ seq 0 p ∈ 𝒫 ℕ 0 , m ∈ ℕ 0 ⟼ p sadd n ∈ ℕ 0 | m ∈ A ∧ n − m ∈ B ∩ 0 ..^ N n ∈ ℕ 0 ⟼ if n = 0 ∅ n − 1 = seq 0 p ∈ 𝒫 ℕ 0 , m ∈ ℕ 0 ⟼ p sadd n ∈ ℕ 0 | m ∈ A ∧ n − m ∈ B ∩ 0 ..^ N n ∈ ℕ 0 ⟼ if n = 0 ∅ n − 1
6 1 2 3 4 5 smueqlem ⊢ φ → A smul B ∩ 0 ..^ N = A ∩ 0 ..^ N smul B ∩ 0 ..^ N ∩ 0 ..^ N