Metamath Proof Explorer


Theorem sn-mul01

Description: mul01 without ax-mulcom . (Contributed by SN, 5-May-2024)

Ref Expression
Assertion sn-mul01 ⊢ A ∈ ℂ → A ⋅ 0 = 0

Proof

Step Hyp Ref Expression
1 id ⊢ A ∈ ℂ → A ∈ ℂ
2 0cnd ⊢ A ∈ ℂ → 0 ∈ ℂ
3 1 2 mulcld ⊢ A ∈ ℂ → A ⋅ 0 ∈ ℂ
4 1 2 2 adddid ⊢ A ∈ ℂ → A ⁢ 0 + 0 = A ⋅ 0 + A ⋅ 0
5 sn-00id ⊢ 0 + 0 = 0
6 5 oveq2i ⊢ A ⁢ 0 + 0 = A ⋅ 0
7 4 6 eqtr3di ⊢ A ∈ ℂ → A ⋅ 0 + A ⋅ 0 = A ⋅ 0
8 3 7 sn-addid0 ⊢ A ∈ ℂ → A ⋅ 0 = 0