Metamath Proof Explorer


Theorem spansnji

Description: The subspace sum of a closed subspace and a one-dimensional subspace equals their join. (Proof suggested by Eric Schechter 1-Jun-2004.) (Contributed by NM, 1-Jun-2004) (New usage is discouraged.)

Ref Expression
Hypotheses spansnj.1 ⊢ A ∈ C ℋ
spansnj.2 ⊢ B ∈ ℋ
Assertion spansnji ⊢ A + ℋ span ⁡ B = A ∨ ℋ span ⁡ B

Proof

Step Hyp Ref Expression
1 spansnj.1 ⊢ A ∈ C ℋ
2 spansnj.2 ⊢ B ∈ ℋ
3 1 chshii ⊢ A ∈ S ℋ
4 2 spansnchi ⊢ span ⁡ B ∈ C ℋ
5 4 chshii ⊢ span ⁡ B ∈ S ℋ
6 3 5 shjshsi ⊢ A ∨ ℋ span ⁡ B = ⊥ ⁡ ⊥ ⁡ A + ℋ span ⁡ B
7 1 chssii ⊢ A ⊆ ℋ
8 1 choccli ⊢ ⊥ ⁡ A ∈ C ℋ
9 8 2 pjhclii ⊢ proj ℎ ⁡ ⊥ ⁡ A ⁡ B ∈ ℋ
10 snssi ⊢ proj ℎ ⁡ ⊥ ⁡ A ⁡ B ∈ ℋ → proj ℎ ⁡ ⊥ ⁡ A ⁡ B ⊆ ℋ
11 9 10 ax-mp ⊢ proj ℎ ⁡ ⊥ ⁡ A ⁡ B ⊆ ℋ
12 7 11 spanuni ⊢ span ⁡ A ∪ proj ℎ ⁡ ⊥ ⁡ A ⁡ B = span ⁡ A + ℋ span ⁡ proj ℎ ⁡ ⊥ ⁡ A ⁡ B
13 spanid ⊢ A ∈ S ℋ → span ⁡ A = A
14 3 13 ax-mp ⊢ span ⁡ A = A
15 14 oveq1i ⊢ span ⁡ A + ℋ span ⁡ proj ℎ ⁡ ⊥ ⁡ A ⁡ B = A + ℋ span ⁡ proj ℎ ⁡ ⊥ ⁡ A ⁡ B
16 7 2 spansnpji ⊢ A ⊆ ⊥ ⁡ span ⁡ proj ℎ ⁡ ⊥ ⁡ A ⁡ B
17 9 spansnchi ⊢ span ⁡ proj ℎ ⁡ ⊥ ⁡ A ⁡ B ∈ C ℋ
18 1 17 osumi ⊢ A ⊆ ⊥ ⁡ span ⁡ proj ℎ ⁡ ⊥ ⁡ A ⁡ B → A + ℋ span ⁡ proj ℎ ⁡ ⊥ ⁡ A ⁡ B = A ∨ ℋ span ⁡ proj ℎ ⁡ ⊥ ⁡ A ⁡ B
19 16 18 ax-mp ⊢ A + ℋ span ⁡ proj ℎ ⁡ ⊥ ⁡ A ⁡ B = A ∨ ℋ span ⁡ proj ℎ ⁡ ⊥ ⁡ A ⁡ B
20 12 15 19 3eqtrri ⊢ A ∨ ℋ span ⁡ proj ℎ ⁡ ⊥ ⁡ A ⁡ B = span ⁡ A ∪ proj ℎ ⁡ ⊥ ⁡ A ⁡ B
21 1 2 spanunsni ⊢ span ⁡ A ∪ B = span ⁡ A ∪ proj ℎ ⁡ ⊥ ⁡ A ⁡ B
22 20 21 eqtr4i ⊢ A ∨ ℋ span ⁡ proj ℎ ⁡ ⊥ ⁡ A ⁡ B = span ⁡ A ∪ B
23 snssi ⊢ B ∈ ℋ → B ⊆ ℋ
24 2 23 ax-mp ⊢ B ⊆ ℋ
25 7 24 spanuni ⊢ span ⁡ A ∪ B = span ⁡ A + ℋ span ⁡ B
26 14 oveq1i ⊢ span ⁡ A + ℋ span ⁡ B = A + ℋ span ⁡ B
27 22 25 26 3eqtrri ⊢ A + ℋ span ⁡ B = A ∨ ℋ span ⁡ proj ℎ ⁡ ⊥ ⁡ A ⁡ B
28 1 17 chjcli ⊢ A ∨ ℋ span ⁡ proj ℎ ⁡ ⊥ ⁡ A ⁡ B ∈ C ℋ
29 27 28 eqeltri ⊢ A + ℋ span ⁡ B ∈ C ℋ
30 29 ococi ⊢ ⊥ ⁡ ⊥ ⁡ A + ℋ span ⁡ B = A + ℋ span ⁡ B
31 6 30 eqtr2i ⊢ A + ℋ span ⁡ B = A ∨ ℋ span ⁡ B