Metamath Proof Explorer


Theorem ssimaexg

Description: The existence of a subimage. (Contributed by FL, 15-Apr-2007)

Ref Expression
Assertion ssimaexg ⊢ A ∈ C ∧ Fun ⁡ F ∧ B ⊆ F A → ∃ x x ⊆ A ∧ B = F x

Proof

Step Hyp Ref Expression
1 imaeq2 ⊢ y = A → F y = F A
2 1 sseq2d ⊢ y = A → B ⊆ F y ↔ B ⊆ F A
3 2 anbi2d ⊢ y = A → Fun ⁡ F ∧ B ⊆ F y ↔ Fun ⁡ F ∧ B ⊆ F A
4 sseq2 ⊢ y = A → x ⊆ y ↔ x ⊆ A
5 4 anbi1d ⊢ y = A → x ⊆ y ∧ B = F x ↔ x ⊆ A ∧ B = F x
6 5 exbidv ⊢ y = A → ∃ x x ⊆ y ∧ B = F x ↔ ∃ x x ⊆ A ∧ B = F x
7 3 6 imbi12d ⊢ y = A → Fun ⁡ F ∧ B ⊆ F y → ∃ x x ⊆ y ∧ B = F x ↔ Fun ⁡ F ∧ B ⊆ F A → ∃ x x ⊆ A ∧ B = F x
8 vex ⊢ y ∈ V
9 8 ssimaex ⊢ Fun ⁡ F ∧ B ⊆ F y → ∃ x x ⊆ y ∧ B = F x
10 7 9 vtoclg ⊢ A ∈ C → Fun ⁡ F ∧ B ⊆ F A → ∃ x x ⊆ A ∧ B = F x
11 10 3impib ⊢ A ∈ C ∧ Fun ⁡ F ∧ B ⊆ F A → ∃ x x ⊆ A ∧ B = F x