Metamath Proof Explorer


Theorem sxsigon

Description: A product sigma-algebra is a sigma-algebra on the product of the bases. (Contributed by Thierry Arnoux, 1-Jun-2017)

Ref Expression
Assertion sxsigon ⊢ S ∈ ⋃ ran ⁡ sigAlgebra ∧ T ∈ ⋃ ran ⁡ sigAlgebra → S × s T ∈ sigAlgebra ⁡ ⋃ S × ⋃ T

Proof

Step Hyp Ref Expression
1 sxsiga ⊢ S ∈ ⋃ ran ⁡ sigAlgebra ∧ T ∈ ⋃ ran ⁡ sigAlgebra → S × s T ∈ ⋃ ran ⁡ sigAlgebra
2 eqid ⊢ ran ⁡ x ∈ S , y ∈ T ⟼ x × y = ran ⁡ x ∈ S , y ∈ T ⟼ x × y
3 eqid ⊢ ⋃ S = ⋃ S
4 eqid ⊢ ⋃ T = ⋃ T
5 2 3 4 txuni2 ⊢ ⋃ S × ⋃ T = ⋃ ran ⁡ x ∈ S , y ∈ T ⟼ x × y
6 2 sxval ⊢ S ∈ ⋃ ran ⁡ sigAlgebra ∧ T ∈ ⋃ ran ⁡ sigAlgebra → S × s T = 𝛔 ⁡ ran ⁡ x ∈ S , y ∈ T ⟼ x × y
7 6 unieqd ⊢ S ∈ ⋃ ran ⁡ sigAlgebra ∧ T ∈ ⋃ ran ⁡ sigAlgebra → ⋃ S × s T = ⋃ 𝛔 ⁡ ran ⁡ x ∈ S , y ∈ T ⟼ x × y
8 mpoexga ⊢ S ∈ ⋃ ran ⁡ sigAlgebra ∧ T ∈ ⋃ ran ⁡ sigAlgebra → x ∈ S , y ∈ T ⟼ x × y ∈ V
9 rnexg ⊢ x ∈ S , y ∈ T ⟼ x × y ∈ V → ran ⁡ x ∈ S , y ∈ T ⟼ x × y ∈ V
10 unisg ⊢ ran ⁡ x ∈ S , y ∈ T ⟼ x × y ∈ V → ⋃ 𝛔 ⁡ ran ⁡ x ∈ S , y ∈ T ⟼ x × y = ⋃ ran ⁡ x ∈ S , y ∈ T ⟼ x × y
11 8 9 10 3syl ⊢ S ∈ ⋃ ran ⁡ sigAlgebra ∧ T ∈ ⋃ ran ⁡ sigAlgebra → ⋃ 𝛔 ⁡ ran ⁡ x ∈ S , y ∈ T ⟼ x × y = ⋃ ran ⁡ x ∈ S , y ∈ T ⟼ x × y
12 7 11 eqtrd ⊢ S ∈ ⋃ ran ⁡ sigAlgebra ∧ T ∈ ⋃ ran ⁡ sigAlgebra → ⋃ S × s T = ⋃ ran ⁡ x ∈ S , y ∈ T ⟼ x × y
13 5 12 eqtr4id ⊢ S ∈ ⋃ ran ⁡ sigAlgebra ∧ T ∈ ⋃ ran ⁡ sigAlgebra → ⋃ S × ⋃ T = ⋃ S × s T
14 issgon ⊢ S × s T ∈ sigAlgebra ⁡ ⋃ S × ⋃ T ↔ S × s T ∈ ⋃ ran ⁡ sigAlgebra ∧ ⋃ S × ⋃ T = ⋃ S × s T
15 1 13 14 sylanbrc ⊢ S ∈ ⋃ ran ⁡ sigAlgebra ∧ T ∈ ⋃ ran ⁡ sigAlgebra → S × s T ∈ sigAlgebra ⁡ ⋃ S × ⋃ T