Metamath Proof Explorer


Theorem tgcgrextend

Description: Link congruence over a pair of line segments. Theorem 2.11 of Schwabhauser p. 29. (Contributed by Thierry Arnoux, 23-Mar-2019) (Shortened by David A. Wheeler and Thierry Arnoux, 22-Apr-2020.)

Ref Expression
Hypotheses tkgeom.p ⊢ P = Base G
tkgeom.d ⊢ - ˙ = dist ⁡ G
tkgeom.i ⊢ I = Itv ⁡ G
tkgeom.g ⊢ φ → G ∈ 𝒢 Tarski
tgcgrextend.a ⊢ φ → A ∈ P
tgcgrextend.b ⊢ φ → B ∈ P
tgcgrextend.c ⊢ φ → C ∈ P
tgcgrextend.d ⊢ φ → D ∈ P
tgcgrextend.e ⊢ φ → E ∈ P
tgcgrextend.f ⊢ φ → F ∈ P
tgcgrextend.1 ⊢ φ → B ∈ A I C
tgcgrextend.2 ⊢ φ → E ∈ D I F
tgcgrextend.3 ⊢ φ → A - ˙ B = D - ˙ E
tgcgrextend.4 ⊢ φ → B - ˙ C = E - ˙ F
Assertion tgcgrextend ⊢ φ → A - ˙ C = D - ˙ F

Proof

Step Hyp Ref Expression
1 tkgeom.p ⊢ P = Base G
2 tkgeom.d ⊢ - ˙ = dist ⁡ G
3 tkgeom.i ⊢ I = Itv ⁡ G
4 tkgeom.g ⊢ φ → G ∈ 𝒢 Tarski
5 tgcgrextend.a ⊢ φ → A ∈ P
6 tgcgrextend.b ⊢ φ → B ∈ P
7 tgcgrextend.c ⊢ φ → C ∈ P
8 tgcgrextend.d ⊢ φ → D ∈ P
9 tgcgrextend.e ⊢ φ → E ∈ P
10 tgcgrextend.f ⊢ φ → F ∈ P
11 tgcgrextend.1 ⊢ φ → B ∈ A I C
12 tgcgrextend.2 ⊢ φ → E ∈ D I F
13 tgcgrextend.3 ⊢ φ → A - ˙ B = D - ˙ E
14 tgcgrextend.4 ⊢ φ → B - ˙ C = E - ˙ F
15 14 adantr ⊢ φ ∧ A = B → B - ˙ C = E - ˙ F
16 simpr ⊢ φ ∧ A = B → A = B
17 16 oveq1d ⊢ φ ∧ A = B → A - ˙ C = B - ˙ C
18 4 adantr ⊢ φ ∧ A = B → G ∈ 𝒢 Tarski
19 5 adantr ⊢ φ ∧ A = B → A ∈ P
20 6 adantr ⊢ φ ∧ A = B → B ∈ P
21 8 adantr ⊢ φ ∧ A = B → D ∈ P
22 9 adantr ⊢ φ ∧ A = B → E ∈ P
23 13 adantr ⊢ φ ∧ A = B → A - ˙ B = D - ˙ E
24 1 2 3 18 19 20 21 22 23 16 tgcgreq ⊢ φ ∧ A = B → D = E
25 24 oveq1d ⊢ φ ∧ A = B → D - ˙ F = E - ˙ F
26 15 17 25 3eqtr4d ⊢ φ ∧ A = B → A - ˙ C = D - ˙ F
27 4 adantr ⊢ φ ∧ A ≠ B → G ∈ 𝒢 Tarski
28 7 adantr ⊢ φ ∧ A ≠ B → C ∈ P
29 5 adantr ⊢ φ ∧ A ≠ B → A ∈ P
30 10 adantr ⊢ φ ∧ A ≠ B → F ∈ P
31 8 adantr ⊢ φ ∧ A ≠ B → D ∈ P
32 6 adantr ⊢ φ ∧ A ≠ B → B ∈ P
33 9 adantr ⊢ φ ∧ A ≠ B → E ∈ P
34 simpr ⊢ φ ∧ A ≠ B → A ≠ B
35 11 adantr ⊢ φ ∧ A ≠ B → B ∈ A I C
36 12 adantr ⊢ φ ∧ A ≠ B → E ∈ D I F
37 13 adantr ⊢ φ ∧ A ≠ B → A - ˙ B = D - ˙ E
38 14 adantr ⊢ φ ∧ A ≠ B → B - ˙ C = E - ˙ F
39 1 2 3 27 29 31 tgcgrtriv ⊢ φ ∧ A ≠ B → A - ˙ A = D - ˙ D
40 1 2 3 27 29 32 31 33 37 tgcgrcomlr ⊢ φ ∧ A ≠ B → B - ˙ A = E - ˙ D
41 1 2 3 27 29 32 28 31 33 30 29 31 34 35 36 37 38 39 40 axtg5seg ⊢ φ ∧ A ≠ B → C - ˙ A = F - ˙ D
42 1 2 3 27 28 29 30 31 41 tgcgrcomlr ⊢ φ ∧ A ≠ B → A - ˙ C = D - ˙ F
43 26 42 pm2.61dane ⊢ φ → A - ˙ C = D - ˙ F