Metamath Proof Explorer


Theorem tgval

Description: The topology generated by a basis. See also tgval2 and tgval3 . (Contributed by NM, 16-Jul-2006) (Revised by Mario Carneiro, 10-Jan-2015)

Ref Expression
Assertion tgval ⊢ B ∈ V → topGen ⁡ B = x | x ⊆ ⋃ B ∩ 𝒫 x

Proof

Step Hyp Ref Expression
1 df-topgen ⊢ topGen = y ∈ V ⟼ x | x ⊆ ⋃ y ∩ 𝒫 x
2 ineq1 ⊢ y = B → y ∩ 𝒫 x = B ∩ 𝒫 x
3 2 unieqd ⊢ y = B → ⋃ y ∩ 𝒫 x = ⋃ B ∩ 𝒫 x
4 3 sseq2d ⊢ y = B → x ⊆ ⋃ y ∩ 𝒫 x ↔ x ⊆ ⋃ B ∩ 𝒫 x
5 4 abbidv ⊢ y = B → x | x ⊆ ⋃ y ∩ 𝒫 x = x | x ⊆ ⋃ B ∩ 𝒫 x
6 elex ⊢ B ∈ V → B ∈ V
7 uniexg ⊢ B ∈ V → ⋃ B ∈ V
8 abssexg ⊢ ⋃ B ∈ V → x | x ⊆ ⋃ B ∧ x ⊆ ⋃ 𝒫 x ∈ V
9 uniin ⊢ ⋃ B ∩ 𝒫 x ⊆ ⋃ B ∩ ⋃ 𝒫 x
10 sstr ⊢ x ⊆ ⋃ B ∩ 𝒫 x ∧ ⋃ B ∩ 𝒫 x ⊆ ⋃ B ∩ ⋃ 𝒫 x → x ⊆ ⋃ B ∩ ⋃ 𝒫 x
11 9 10 mpan2 ⊢ x ⊆ ⋃ B ∩ 𝒫 x → x ⊆ ⋃ B ∩ ⋃ 𝒫 x
12 ssin ⊢ x ⊆ ⋃ B ∧ x ⊆ ⋃ 𝒫 x ↔ x ⊆ ⋃ B ∩ ⋃ 𝒫 x
13 11 12 sylibr ⊢ x ⊆ ⋃ B ∩ 𝒫 x → x ⊆ ⋃ B ∧ x ⊆ ⋃ 𝒫 x
14 13 ss2abi ⊢ x | x ⊆ ⋃ B ∩ 𝒫 x ⊆ x | x ⊆ ⋃ B ∧ x ⊆ ⋃ 𝒫 x
15 ssexg ⊢ x | x ⊆ ⋃ B ∩ 𝒫 x ⊆ x | x ⊆ ⋃ B ∧ x ⊆ ⋃ 𝒫 x ∧ x | x ⊆ ⋃ B ∧ x ⊆ ⋃ 𝒫 x ∈ V → x | x ⊆ ⋃ B ∩ 𝒫 x ∈ V
16 14 15 mpan ⊢ x | x ⊆ ⋃ B ∧ x ⊆ ⋃ 𝒫 x ∈ V → x | x ⊆ ⋃ B ∩ 𝒫 x ∈ V
17 7 8 16 3syl ⊢ B ∈ V → x | x ⊆ ⋃ B ∩ 𝒫 x ∈ V
18 1 5 6 17 fvmptd3 ⊢ B ∈ V → topGen ⁡ B = x | x ⊆ ⋃ B ∩ 𝒫 x