Metamath Proof Explorer


Theorem tmachlem-agreeself

Description: Any tape belongs to its own agreement set. (Contributed by Ender Ting, 27-Jul-2026)

Ref Expression
Hypotheses tmach.finalph ⊢ φ → U ∈ Fin
tmach.exindex ⊢ φ → I ∈ V
tmach.tapelist ⊢ φ → T = U I
tmach.scanmap ⊢ φ → S : T ⟶ 𝒫 I ∩ Fin
tmach.agreemap ⊢ φ → A = z ∈ T ⟼ y ∈ T | y ↾ S ⁡ z = z ↾ S ⁡ z
tmach.agreement ⊢ φ → ∀ z ∈ T ∀ y ∈ A ⁡ z S ⁡ y = S ⁡ z
Assertion tmachlem-agreeself ⊢ φ ∧ a ∈ T → a ∈ A ⁡ a

Proof

Step Hyp Ref Expression
1 tmach.finalph ⊢ φ → U ∈ Fin
2 tmach.exindex ⊢ φ → I ∈ V
3 tmach.tapelist ⊢ φ → T = U I
4 tmach.scanmap ⊢ φ → S : T ⟶ 𝒫 I ∩ Fin
5 tmach.agreemap ⊢ φ → A = z ∈ T ⟼ y ∈ T | y ↾ S ⁡ z = z ↾ S ⁡ z
6 tmach.agreement ⊢ φ → ∀ z ∈ T ∀ y ∈ A ⁡ z S ⁡ y = S ⁡ z
7 reseq1 ⊢ y = a → y ↾ S ⁡ a = a ↾ S ⁡ a
8 tbtru ⊢ y ↾ S ⁡ a = a ↾ S ⁡ a ↔ y ↾ S ⁡ a = a ↾ S ⁡ a ↔ ⊤
9 7 8 sylib ⊢ y = a → y ↾ S ⁡ a = a ↾ S ⁡ a ↔ ⊤
10 simpr ⊢ φ ∧ a ∈ T → a ∈ T
11 trud ⊢ φ ∧ a ∈ T → ⊤
12 9 10 11 elrabd ⊢ φ ∧ a ∈ T → a ∈ y ∈ T | y ↾ S ⁡ a = a ↾ S ⁡ a
13 fveq2 ⊢ z = a → S ⁡ z = S ⁡ a
14 13 reseq2d ⊢ z = a → y ↾ S ⁡ z = y ↾ S ⁡ a
15 id ⊢ z = a → z = a
16 15 13 reseq12d ⊢ z = a → z ↾ S ⁡ z = a ↾ S ⁡ a
17 14 16 eqeq12d ⊢ z = a → y ↾ S ⁡ z = z ↾ S ⁡ z ↔ y ↾ S ⁡ a = a ↾ S ⁡ a
18 17 rabbidv ⊢ z = a → y ∈ T | y ↾ S ⁡ z = z ↾ S ⁡ z = y ∈ T | y ↾ S ⁡ a = a ↾ S ⁡ a
19 5 adantr ⊢ φ ∧ a ∈ T → A = z ∈ T ⟼ y ∈ T | y ↾ S ⁡ z = z ↾ S ⁡ z
20 1 2 3 4 5 6 tmachlem-extapes ⊢ φ → T ∈ V
21 ssrab2 ⊢ y ∈ T | y ↾ S ⁡ a = a ↾ S ⁡ a ⊆ T
22 21 a1i ⊢ φ → y ∈ T | y ↾ S ⁡ a = a ↾ S ⁡ a ⊆ T
23 20 22 ssexd ⊢ φ → y ∈ T | y ↾ S ⁡ a = a ↾ S ⁡ a ∈ V
24 23 adantr ⊢ φ ∧ a ∈ T → y ∈ T | y ↾ S ⁡ a = a ↾ S ⁡ a ∈ V
25 18 19 10 24 fvmptd4 ⊢ φ ∧ a ∈ T → A ⁡ a = y ∈ T | y ↾ S ⁡ a = a ↾ S ⁡ a
26 12 25 eleqtrrd ⊢ φ ∧ a ∈ T → a ∈ A ⁡ a