Metamath Proof Explorer


Theorem uneqin

Description: Equality of union and intersection is equivalent to equality of the arguments. (Contributed by NM, 16-Apr-2006) (Proof shortened by Andrew Salmon, 26-Jun-2011)

Ref Expression
Assertion uneqin ⊢ A ∪ B = A ∩ B ↔ A = B

Proof

Step Hyp Ref Expression
1 eqimss ⊢ A ∪ B = A ∩ B → A ∪ B ⊆ A ∩ B
2 unss ⊢ A ⊆ A ∩ B ∧ B ⊆ A ∩ B ↔ A ∪ B ⊆ A ∩ B
3 ssin ⊢ A ⊆ A ∧ A ⊆ B ↔ A ⊆ A ∩ B
4 sstr ⊢ A ⊆ A ∧ A ⊆ B → A ⊆ B
5 3 4 sylbir ⊢ A ⊆ A ∩ B → A ⊆ B
6 ssin ⊢ B ⊆ A ∧ B ⊆ B ↔ B ⊆ A ∩ B
7 simpl ⊢ B ⊆ A ∧ B ⊆ B → B ⊆ A
8 6 7 sylbir ⊢ B ⊆ A ∩ B → B ⊆ A
9 5 8 anim12i ⊢ A ⊆ A ∩ B ∧ B ⊆ A ∩ B → A ⊆ B ∧ B ⊆ A
10 2 9 sylbir ⊢ A ∪ B ⊆ A ∩ B → A ⊆ B ∧ B ⊆ A
11 1 10 syl ⊢ A ∪ B = A ∩ B → A ⊆ B ∧ B ⊆ A
12 eqss ⊢ A = B ↔ A ⊆ B ∧ B ⊆ A
13 11 12 sylibr ⊢ A ∪ B = A ∩ B → A = B
14 unidm ⊢ A ∪ A = A
15 inidm ⊢ A ∩ A = A
16 14 15 eqtr4i ⊢ A ∪ A = A ∩ A
17 uneq2 ⊢ A = B → A ∪ A = A ∪ B
18 ineq2 ⊢ A = B → A ∩ A = A ∩ B
19 16 17 18 3eqtr3a ⊢ A = B → A ∪ B = A ∩ B
20 13 19 impbii ⊢ A ∪ B = A ∩ B ↔ A = B