Metamath Proof Explorer


Theorem vrgpf

Description: The mapping from the index set to the generators is a function into the free group. (Contributed by Mario Carneiro, 2-Oct-2015)

Ref Expression
Hypotheses vrgpfval.r ˙=~FGI
vrgpfval.u U=varFGrpI
vrgpf.m G=freeGrpI
vrgpf.x X=BaseG
Assertion vrgpf IVU:IX

Proof

Step Hyp Ref Expression
1 vrgpfval.r ˙=~FGI
2 vrgpfval.u U=varFGrpI
3 vrgpf.m G=freeGrpI
4 vrgpf.x X=BaseG
5 1 2 vrgpfval IVU=jI⟨“j”⟩˙
6 0ex V
7 6 prid1 1𝑜
8 df2o3 2𝑜=1𝑜
9 7 8 eleqtrri 2𝑜
10 opelxpi jI2𝑜jI×2𝑜
11 9 10 mpan2 jIjI×2𝑜
12 11 adantl IVjIjI×2𝑜
13 12 s1cld IVjI⟨“j”⟩WordI×2𝑜
14 2on 2𝑜On
15 xpexg IV2𝑜OnI×2𝑜V
16 14 15 mpan2 IVI×2𝑜V
17 16 adantr IVjII×2𝑜V
18 wrdexg I×2𝑜VWordI×2𝑜V
19 fvi WordI×2𝑜VIWordI×2𝑜=WordI×2𝑜
20 17 18 19 3syl IVjIIWordI×2𝑜=WordI×2𝑜
21 13 20 eleqtrrd IVjI⟨“j”⟩IWordI×2𝑜
22 eqid IWordI×2𝑜=IWordI×2𝑜
23 3 1 22 4 frgpeccl ⟨“j”⟩IWordI×2𝑜⟨“j”⟩˙X
24 21 23 syl IVjI⟨“j”⟩˙X
25 5 24 fmpt3d IVU:IX