Metamath Proof Explorer


Theorem xpexr

Description: If a Cartesian product is a set, one of its components must be a set. (Contributed by NM, 27-Aug-2006)

Ref Expression
Assertion xpexr ⊢ A × B ∈ C → A ∈ V ∨ B ∈ V

Proof

Step Hyp Ref Expression
1 0ex ⊢ ∅ ∈ V
2 eleq1 ⊢ A = ∅ → A ∈ V ↔ ∅ ∈ V
3 1 2 mpbiri ⊢ A = ∅ → A ∈ V
4 3 pm2.24d ⊢ A = ∅ → ¬ A ∈ V → B ∈ V
5 4 a1d ⊢ A = ∅ → A × B ∈ C → ¬ A ∈ V → B ∈ V
6 rnexg ⊢ A × B ∈ C → ran ⁡ A × B ∈ V
7 rnxp ⊢ A ≠ ∅ → ran ⁡ A × B = B
8 7 eleq1d ⊢ A ≠ ∅ → ran ⁡ A × B ∈ V ↔ B ∈ V
9 6 8 imbitrid ⊢ A ≠ ∅ → A × B ∈ C → B ∈ V
10 9 a1dd ⊢ A ≠ ∅ → A × B ∈ C → ¬ A ∈ V → B ∈ V
11 5 10 pm2.61ine ⊢ A × B ∈ C → ¬ A ∈ V → B ∈ V
12 11 orrd ⊢ A × B ∈ C → A ∈ V ∨ B ∈ V