Metamath Proof Explorer


Theorem xpsrngd

Description: A product of two non-unital rings is a non-unital ring ( xpsmnd analog). (Contributed by AV, 22-Feb-2025)

Ref Expression
Hypotheses xpsrngd.y ⊢ Y = S × 𝑠 R
xpsrngd.s ⊢ φ → S ∈ Rng
xpsrngd.r ⊢ φ → R ∈ Rng
Assertion xpsrngd ⊢ φ → Y ∈ Rng

Proof

Step Hyp Ref Expression
1 xpsrngd.y ⊢ Y = S × 𝑠 R
2 xpsrngd.s ⊢ φ → S ∈ Rng
3 xpsrngd.r ⊢ φ → R ∈ Rng
4 eqid ⊢ Base S = Base S
5 eqid ⊢ Base R = Base R
6 eqid ⊢ x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y = x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y
7 eqid ⊢ Scalar ⁡ S = Scalar ⁡ S
8 eqid ⊢ Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R = Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R
9 1 4 5 2 3 6 7 8 xpsval ⊢ φ → Y = x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y -1 “ 𝑠 Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R
10 6 xpsff1o2 ⊢ x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y : Base S × Base R ⟶ 1-1 onto ran ⁡ x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y
11 1 4 5 2 3 6 7 8 xpsrnbas ⊢ φ → ran ⁡ x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y = Base Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R
12 11 f1oeq3d ⊢ φ → x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y : Base S × Base R ⟶ 1-1 onto ran ⁡ x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y ↔ x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y : Base S × Base R ⟶ 1-1 onto Base Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R
13 10 12 mpbii ⊢ φ → x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y : Base S × Base R ⟶ 1-1 onto Base Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R
14 f1ocnv ⊢ x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y : Base S × Base R ⟶ 1-1 onto Base Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R → x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y -1 : Base Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R ⟶ 1-1 onto Base S × Base R
15 f1of1 ⊢ x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y -1 : Base Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R ⟶ 1-1 onto Base S × Base R → x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y -1 : Base Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R ⟶ 1-1 Base S × Base R
16 13 14 15 3syl ⊢ φ → x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y -1 : Base Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R ⟶ 1-1 Base S × Base R
17 2on ⊢ 2 𝑜 ∈ On
18 17 a1i ⊢ φ → 2 𝑜 ∈ On
19 fvexd ⊢ φ → Scalar ⁡ S ∈ V
20 xpscf ⊢ ∅ S 1 𝑜 R : 2 𝑜 ⟶ Rng ↔ S ∈ Rng ∧ R ∈ Rng
21 2 3 20 sylanbrc ⊢ φ → ∅ S 1 𝑜 R : 2 𝑜 ⟶ Rng
22 8 18 19 21 prdsrngd ⊢ φ → Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R ∈ Rng
23 eqid ⊢ x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y -1 “ 𝑠 Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R = x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y -1 “ 𝑠 Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R
24 eqid ⊢ Base Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R = Base Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R
25 23 24 imasrngf1 ⊢ x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y -1 : Base Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R ⟶ 1-1 Base S × Base R ∧ Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R ∈ Rng → x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y -1 “ 𝑠 Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R ∈ Rng
26 16 22 25 syl2anc ⊢ φ → x ∈ Base S , y ∈ Base R ⟼ ∅ x 1 𝑜 y -1 “ 𝑠 Scalar ⁡ S ⨉ 𝑠 ∅ S 1 𝑜 R ∈ Rng
27 9 26 eqeltrd ⊢ φ → Y ∈ Rng