Metamath Proof Explorer


Theorem xptrrel

Description: The cross product is always a transitive relation. (Contributed by RP, 24-Dec-2019)

Ref Expression
Assertion xptrrel ⊢ A × B ∘ A × B ⊆ A × B

Proof

Step Hyp Ref Expression
1 inss1 ⊢ dom ⁡ A × B ∩ ran ⁡ A × B ⊆ dom ⁡ A × B
2 dmxpss ⊢ dom ⁡ A × B ⊆ A
3 1 2 sstri ⊢ dom ⁡ A × B ∩ ran ⁡ A × B ⊆ A
4 inss2 ⊢ dom ⁡ A × B ∩ ran ⁡ A × B ⊆ ran ⁡ A × B
5 rnxpss ⊢ ran ⁡ A × B ⊆ B
6 4 5 sstri ⊢ dom ⁡ A × B ∩ ran ⁡ A × B ⊆ B
7 3 6 ssini ⊢ dom ⁡ A × B ∩ ran ⁡ A × B ⊆ A ∩ B
8 eqimss ⊢ A ∩ B = ∅ → A ∩ B ⊆ ∅
9 7 8 sstrid ⊢ A ∩ B = ∅ → dom ⁡ A × B ∩ ran ⁡ A × B ⊆ ∅
10 ss0 ⊢ dom ⁡ A × B ∩ ran ⁡ A × B ⊆ ∅ → dom ⁡ A × B ∩ ran ⁡ A × B = ∅
11 9 10 syl ⊢ A ∩ B = ∅ → dom ⁡ A × B ∩ ran ⁡ A × B = ∅
12 11 coemptyd ⊢ A ∩ B = ∅ → A × B ∘ A × B = ∅
13 0ss ⊢ ∅ ⊆ A × B
14 12 13 eqsstrdi ⊢ A ∩ B = ∅ → A × B ∘ A × B ⊆ A × B
15 neqne ⊢ ¬ A ∩ B = ∅ → A ∩ B ≠ ∅
16 15 xpcoidgend ⊢ ¬ A ∩ B = ∅ → A × B ∘ A × B = A × B
17 ssid ⊢ A × B ⊆ A × B
18 16 17 eqsstrdi ⊢ ¬ A ∩ B = ∅ → A × B ∘ A × B ⊆ A × B
19 14 18 pm2.61i ⊢ A × B ∘ A × B ⊆ A × B