Metamath Proof Explorer


Theorem zringndrg

Description: The integers are not a division ring, and therefore not a field. (Contributed by AV, 22-Oct-2021)

Ref Expression
Assertion zringndrg ⊢ ℤ ring ∉ DivRing

Proof

Step Hyp Ref Expression
1 1ne2 ⊢ 1 ≠ 2
2 1 nesymi ⊢ ¬ 2 = 1
3 2re ⊢ 2 ∈ ℝ
4 0le2 ⊢ 0 ≤ 2
5 absid ⊢ 2 ∈ ℝ ∧ 0 ≤ 2 → 2 = 2
6 3 4 5 mp2an ⊢ 2 = 2
7 6 eqeq1i ⊢ 2 = 1 ↔ 2 = 1
8 2 7 mtbir ⊢ ¬ 2 = 1
9 8 intnan ⊢ ¬ 2 ∈ ℤ ∧ 2 = 1
10 zringunit ⊢ 2 ∈ Unit ⁡ ℤ ring ↔ 2 ∈ ℤ ∧ 2 = 1
11 9 10 mtbir ⊢ ¬ 2 ∈ Unit ⁡ ℤ ring
12 zringbas ⊢ ℤ = Base ℤ ring
13 eqid ⊢ Unit ⁡ ℤ ring = Unit ⁡ ℤ ring
14 zring0 ⊢ 0 = 0 ℤ ring
15 12 13 14 isdrng ⊢ ℤ ring ∈ DivRing ↔ ℤ ring ∈ Ring ∧ Unit ⁡ ℤ ring = ℤ ∖ 0
16 2z ⊢ 2 ∈ ℤ
17 2ne0 ⊢ 2 ≠ 0
18 eldifsn ⊢ 2 ∈ ℤ ∖ 0 ↔ 2 ∈ ℤ ∧ 2 ≠ 0
19 16 17 18 mpbir2an ⊢ 2 ∈ ℤ ∖ 0
20 id ⊢ Unit ⁡ ℤ ring = ℤ ∖ 0 → Unit ⁡ ℤ ring = ℤ ∖ 0
21 19 20 eleqtrrid ⊢ Unit ⁡ ℤ ring = ℤ ∖ 0 → 2 ∈ Unit ⁡ ℤ ring
22 15 21 simplbiim ⊢ ℤ ring ∈ DivRing → 2 ∈ Unit ⁡ ℤ ring
23 11 22 mto ⊢ ¬ ℤ ring ∈ DivRing
24 23 nelir ⊢ ℤ ring ∉ DivRing