Metamath Proof Explorer


Theorem adcnlaz

Description: The adjunction of an integer to the ring of integers yields the integers. (Contributed by AV, 25-Oct-2026)

Ref Expression
Assertion adcnlaz ( 𝑆 ∈ ℤ → ( Z[]l ‘ 𝑆 ) = ℤ )

Proof

Step Hyp Ref Expression
1 zcn ⊢ ( 𝑆 ∈ ℤ → 𝑆 ∈ ℂ )
2 ellaz ⊢ ( 𝑆 ∈ ℂ → ( 𝑠 ∈ ( Z[]l ‘ 𝑆 ) ↔ ( 𝑠 ∈ ℂ ∧ ∃ 𝑎 ∈ ℤ ∃ 𝑏 ∈ ℤ 𝑠 = ( 𝑎 + ( 𝑏 · 𝑆 ) ) ) ) )
3 1 2 syl ⊢ ( 𝑆 ∈ ℤ → ( 𝑠 ∈ ( Z[]l ‘ 𝑆 ) ↔ ( 𝑠 ∈ ℂ ∧ ∃ 𝑎 ∈ ℤ ∃ 𝑏 ∈ ℤ 𝑠 = ( 𝑎 + ( 𝑏 · 𝑆 ) ) ) ) )
4 simprl ⊢ ( ( ( 𝑆 ∈ ℤ ∧ 𝑠 ∈ ℂ ) ∧ ( 𝑎 ∈ ℤ ∧ 𝑏 ∈ ℤ ) ) → 𝑎 ∈ ℤ )
5 simpr ⊢ ( ( 𝑎 ∈ ℤ ∧ 𝑏 ∈ ℤ ) → 𝑏 ∈ ℤ )
6 simpl ⊢ ( ( 𝑆 ∈ ℤ ∧ 𝑠 ∈ ℂ ) → 𝑆 ∈ ℤ )
7 zmulcl ⊢ ( ( 𝑏 ∈ ℤ ∧ 𝑆 ∈ ℤ ) → ( 𝑏 · 𝑆 ) ∈ ℤ )
8 5 6 7 syl2anr ⊢ ( ( ( 𝑆 ∈ ℤ ∧ 𝑠 ∈ ℂ ) ∧ ( 𝑎 ∈ ℤ ∧ 𝑏 ∈ ℤ ) ) → ( 𝑏 · 𝑆 ) ∈ ℤ )
9 4 8 zaddcld ⊢ ( ( ( 𝑆 ∈ ℤ ∧ 𝑠 ∈ ℂ ) ∧ ( 𝑎 ∈ ℤ ∧ 𝑏 ∈ ℤ ) ) → ( 𝑎 + ( 𝑏 · 𝑆 ) ) ∈ ℤ )
10 eleq1 ⊢ ( 𝑠 = ( 𝑎 + ( 𝑏 · 𝑆 ) ) → ( 𝑠 ∈ ℤ ↔ ( 𝑎 + ( 𝑏 · 𝑆 ) ) ∈ ℤ ) )
11 9 10 syl5ibrcom ⊢ ( ( ( 𝑆 ∈ ℤ ∧ 𝑠 ∈ ℂ ) ∧ ( 𝑎 ∈ ℤ ∧ 𝑏 ∈ ℤ ) ) → ( 𝑠 = ( 𝑎 + ( 𝑏 · 𝑆 ) ) → 𝑠 ∈ ℤ ) )
12 11 rexlimdvva ⊢ ( ( 𝑆 ∈ ℤ ∧ 𝑠 ∈ ℂ ) → ( ∃ 𝑎 ∈ ℤ ∃ 𝑏 ∈ ℤ 𝑠 = ( 𝑎 + ( 𝑏 · 𝑆 ) ) → 𝑠 ∈ ℤ ) )
13 12 expimpd ⊢ ( 𝑆 ∈ ℤ → ( ( 𝑠 ∈ ℂ ∧ ∃ 𝑎 ∈ ℤ ∃ 𝑏 ∈ ℤ 𝑠 = ( 𝑎 + ( 𝑏 · 𝑆 ) ) ) → 𝑠 ∈ ℤ ) )
14 3 13 sylbid ⊢ ( 𝑆 ∈ ℤ → ( 𝑠 ∈ ( Z[]l ‘ 𝑆 ) → 𝑠 ∈ ℤ ) )
15 zellaz ⊢ ( ( 𝑆 ∈ ℂ ∧ 𝑠 ∈ ℤ ) → 𝑠 ∈ ( Z[]l ‘ 𝑆 ) )
16 15 ex ⊢ ( 𝑆 ∈ ℂ → ( 𝑠 ∈ ℤ → 𝑠 ∈ ( Z[]l ‘ 𝑆 ) ) )
17 1 16 syl ⊢ ( 𝑆 ∈ ℤ → ( 𝑠 ∈ ℤ → 𝑠 ∈ ( Z[]l ‘ 𝑆 ) ) )
18 14 17 impbid ⊢ ( 𝑆 ∈ ℤ → ( 𝑠 ∈ ( Z[]l ‘ 𝑆 ) ↔ 𝑠 ∈ ℤ ) )
19 18 eqrdv ⊢ ( 𝑆 ∈ ℤ → ( Z[]l ‘ 𝑆 ) = ℤ )