Metamath Proof Explorer


Theorem bj-restsn0

Description: An elementwise intersection on the singleton on the empty set is the singleton on the empty set. Special case of bj-restsn and bj-restsnss2 . TODO: this is restsn . (Contributed by BJ, 27-Apr-2021)

Ref Expression
Assertion bj-restsn0 ( 𝐴𝑉 → ( { ∅ } ↾t 𝐴 ) = { ∅ } )

Proof

Step Hyp Ref Expression
1 0ss ∅ ⊆ 𝐴
2 bj-restsnss2 ( ( 𝐴𝑉 ∧ ∅ ⊆ 𝐴 ) → ( { ∅ } ↾t 𝐴 ) = { ∅ } )
3 1 2 mpan2 ( 𝐴𝑉 → ( { ∅ } ↾t 𝐴 ) = { ∅ } )