Metamath Proof Explorer


Theorem bropabg

Description: Equivalence for two classes related by an ordered-pair class abstraction. A generalization of brslts . (Contributed by RP, 26-Sep-2024)

Ref Expression
Hypotheses bropabg.xA ⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜓 ) )
bropabg.yB ⊢ ( 𝑦 = 𝐵 → ( 𝜓 ↔ 𝜒 ) )
bropabg.R ⊢ 𝑅 = { ⟨ 𝑥 , 𝑦 ⟩ ∣ 𝜑 }
Assertion bropabg ( 𝐴 𝑅 𝐵 ↔ ( ( 𝐴 ∈ V ∧ 𝐵 ∈ V ) ∧ 𝜒 ) )

Proof

Step Hyp Ref Expression
1 bropabg.xA ⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜓 ) )
2 bropabg.yB ⊢ ( 𝑦 = 𝐵 → ( 𝜓 ↔ 𝜒 ) )
3 bropabg.R ⊢ 𝑅 = { ⟨ 𝑥 , 𝑦 ⟩ ∣ 𝜑 }
4 3 bropaex12 ⊢ ( 𝐴 𝑅 𝐵 → ( 𝐴 ∈ V ∧ 𝐵 ∈ V ) )
5 1 2 3 brabg ⊢ ( ( 𝐴 ∈ V ∧ 𝐵 ∈ V ) → ( 𝐴 𝑅 𝐵 ↔ 𝜒 ) )
6 4 5 biadanii ⊢ ( 𝐴 𝑅 𝐵 ↔ ( ( 𝐴 ∈ V ∧ 𝐵 ∈ V ) ∧ 𝜒 ) )