Metamath Proof Explorer


Theorem cbviotadavw

Description: Change bound variable in a description binder. Deduction form. (Contributed by GG, 14-Aug-2025)

Ref Expression
Hypothesis cbviotadavw.1 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝜓 ↔ 𝜒 ) )
Assertion cbviotadavw ( 𝜑 → ( ℩ 𝑥 𝜓 ) = ( ℩ 𝑦 𝜒 ) )

Proof

Step Hyp Ref Expression
1 cbviotadavw.1 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝜓 ↔ 𝜒 ) )
2 1 cbvabdavw ⊢ ( 𝜑 → { 𝑥 ∣ 𝜓 } = { 𝑦 ∣ 𝜒 } )
3 2 eqeq1d ⊢ ( 𝜑 → ( { 𝑥 ∣ 𝜓 } = { 𝑡 } ↔ { 𝑦 ∣ 𝜒 } = { 𝑡 } ) )
4 3 abbidv ⊢ ( 𝜑 → { 𝑡 ∣ { 𝑥 ∣ 𝜓 } = { 𝑡 } } = { 𝑡 ∣ { 𝑦 ∣ 𝜒 } = { 𝑡 } } )
5 4 unieqd ⊢ ( 𝜑 → ∪ { 𝑡 ∣ { 𝑥 ∣ 𝜓 } = { 𝑡 } } = ∪ { 𝑡 ∣ { 𝑦 ∣ 𝜒 } = { 𝑡 } } )
6 df-iota ⊢ ( ℩ 𝑥 𝜓 ) = ∪ { 𝑡 ∣ { 𝑥 ∣ 𝜓 } = { 𝑡 } }
7 df-iota ⊢ ( ℩ 𝑦 𝜒 ) = ∪ { 𝑡 ∣ { 𝑦 ∣ 𝜒 } = { 𝑡 } }
8 5 6 7 3eqtr4g ⊢ ( 𝜑 → ( ℩ 𝑥 𝜓 ) = ( ℩ 𝑦 𝜒 ) )