Metamath Proof Explorer


Theorem cbvrabdavw2

Description: Change bound variable and domain in restricted class abstractions. Deduction form. (Contributed by GG, 14-Aug-2025)

Ref Expression
Hypotheses cbvrabdavw2.1 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝜓 ↔ 𝜒 ) )
cbvrabdavw2.2 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → 𝐴 = 𝐵 )
Assertion cbvrabdavw2 ( 𝜑 → { 𝑥 ∈ 𝐴 ∣ 𝜓 } = { 𝑦 ∈ 𝐵 ∣ 𝜒 } )

Proof

Step Hyp Ref Expression
1 cbvrabdavw2.1 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝜓 ↔ 𝜒 ) )
2 cbvrabdavw2.2 ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → 𝐴 = 𝐵 )
3 eleq1w ⊢ ( 𝑥 = 𝑦 → ( 𝑥 ∈ 𝐴 ↔ 𝑦 ∈ 𝐴 ) )
4 3 adantl ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝑥 ∈ 𝐴 ↔ 𝑦 ∈ 𝐴 ) )
5 2 eleq2d ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝑦 ∈ 𝐴 ↔ 𝑦 ∈ 𝐵 ) )
6 4 5 bitrd ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( 𝑥 ∈ 𝐴 ↔ 𝑦 ∈ 𝐵 ) )
7 6 1 anbi12d ⊢ ( ( 𝜑 ∧ 𝑥 = 𝑦 ) → ( ( 𝑥 ∈ 𝐴 ∧ 𝜓 ) ↔ ( 𝑦 ∈ 𝐵 ∧ 𝜒 ) ) )
8 7 cbvabdavw ⊢ ( 𝜑 → { 𝑥 ∣ ( 𝑥 ∈ 𝐴 ∧ 𝜓 ) } = { 𝑦 ∣ ( 𝑦 ∈ 𝐵 ∧ 𝜒 ) } )
9 df-rab ⊢ { 𝑥 ∈ 𝐴 ∣ 𝜓 } = { 𝑥 ∣ ( 𝑥 ∈ 𝐴 ∧ 𝜓 ) }
10 df-rab ⊢ { 𝑦 ∈ 𝐵 ∣ 𝜒 } = { 𝑦 ∣ ( 𝑦 ∈ 𝐵 ∧ 𝜒 ) }
11 8 9 10 3eqtr4g ⊢ ( 𝜑 → { 𝑥 ∈ 𝐴 ∣ 𝜓 } = { 𝑦 ∈ 𝐵 ∣ 𝜒 } )