Metamath Proof Explorer


Theorem chnsuslle

Description: Length of a subsequence is bounded by the length of original chain. (Contributed by Ender Ting, 30-Jan-2026)

Ref Expression
Hypotheses chnsubseq.1 ⊢ ( 𝜑 → 𝑊 ∈ ( < Chain 𝐴 ) )
chnsubseq.2 ⊢ ( 𝜑 → 𝐼 ∈ ( < Chain ( 0 ..^ ( ♯ ‘ 𝑊 ) ) ) )
chnsubseq.3 ⊢ ( 𝜑 → < Po 𝐴 )
Assertion chnsuslle ( 𝜑 → ( ♯ ‘ ( 𝑊 ∘ 𝐼 ) ) ≤ ( ♯ ‘ 𝑊 ) )

Proof

Step Hyp Ref Expression
1 chnsubseq.1 ⊢ ( 𝜑 → 𝑊 ∈ ( < Chain 𝐴 ) )
2 chnsubseq.2 ⊢ ( 𝜑 → 𝐼 ∈ ( < Chain ( 0 ..^ ( ♯ ‘ 𝑊 ) ) ) )
3 chnsubseq.3 ⊢ ( 𝜑 → < Po 𝐴 )
4 ltso ⊢ < Or ℝ
5 sopo ⊢ ( < Or ℝ → < Po ℝ )
6 4 5 mp1i ⊢ ( 𝜑 → < Po ℝ )
7 fzossz ⊢ ( 0 ..^ ( ♯ ‘ 𝑊 ) ) ⊆ ℤ
8 zssre ⊢ ℤ ⊆ ℝ
9 7 8 sstri ⊢ ( 0 ..^ ( ♯ ‘ 𝑊 ) ) ⊆ ℝ
10 9 a1i ⊢ ( 𝜑 → ( 0 ..^ ( ♯ ‘ 𝑊 ) ) ⊆ ℝ )
11 poss ⊢ ( ( 0 ..^ ( ♯ ‘ 𝑊 ) ) ⊆ ℝ → ( < Po ℝ → < Po ( 0 ..^ ( ♯ ‘ 𝑊 ) ) ) )
12 10 11 syl ⊢ ( 𝜑 → ( < Po ℝ → < Po ( 0 ..^ ( ♯ ‘ 𝑊 ) ) ) )
13 6 12 mpd ⊢ ( 𝜑 → < Po ( 0 ..^ ( ♯ ‘ 𝑊 ) ) )
14 ovexd ⊢ ( 𝜑 → ( 0 ..^ ( ♯ ‘ 𝑊 ) ) ∈ V )
15 13 2 14 chnpolleha ⊢ ( 𝜑 → ( ♯ ‘ 𝐼 ) ≤ ( ♯ ‘ ( 0 ..^ ( ♯ ‘ 𝑊 ) ) ) )
16 1 2 chnsubseqwl ⊢ ( 𝜑 → ( ♯ ‘ ( 𝑊 ∘ 𝐼 ) ) = ( ♯ ‘ 𝐼 ) )
17 1 chnwrd ⊢ ( 𝜑 → 𝑊 ∈ Word 𝐴 )
18 lencl ⊢ ( 𝑊 ∈ Word 𝐴 → ( ♯ ‘ 𝑊 ) ∈ ℕ0 )
19 17 18 syl ⊢ ( 𝜑 → ( ♯ ‘ 𝑊 ) ∈ ℕ0 )
20 hashfzo0 ⊢ ( ( ♯ ‘ 𝑊 ) ∈ ℕ0 → ( ♯ ‘ ( 0 ..^ ( ♯ ‘ 𝑊 ) ) ) = ( ♯ ‘ 𝑊 ) )
21 19 20 syl ⊢ ( 𝜑 → ( ♯ ‘ ( 0 ..^ ( ♯ ‘ 𝑊 ) ) ) = ( ♯ ‘ 𝑊 ) )
22 21 eqcomd ⊢ ( 𝜑 → ( ♯ ‘ 𝑊 ) = ( ♯ ‘ ( 0 ..^ ( ♯ ‘ 𝑊 ) ) ) )
23 15 16 22 3brtr4d ⊢ ( 𝜑 → ( ♯ ‘ ( 𝑊 ∘ 𝐼 ) ) ≤ ( ♯ ‘ 𝑊 ) )