Metamath Proof Explorer


Theorem cotcl

Description: The closure of the cotangent function with a complex argument. (Contributed by David A. Wheeler, 15-Mar-2014)

Ref Expression
Assertion cotcl ( ( 𝐴 ∈ ℂ ∧ ( sin ‘ 𝐴 ) ≠ 0 ) → ( cot ‘ 𝐴 ) ∈ ℂ )

Proof

Step Hyp Ref Expression
1 cotval ⊢ ( ( 𝐴 ∈ ℂ ∧ ( sin ‘ 𝐴 ) ≠ 0 ) → ( cot ‘ 𝐴 ) = ( ( cos ‘ 𝐴 ) / ( sin ‘ 𝐴 ) ) )
2 coscl ⊢ ( 𝐴 ∈ ℂ → ( cos ‘ 𝐴 ) ∈ ℂ )
3 2 adantr ⊢ ( ( 𝐴 ∈ ℂ ∧ ( sin ‘ 𝐴 ) ≠ 0 ) → ( cos ‘ 𝐴 ) ∈ ℂ )
4 sincl ⊢ ( 𝐴 ∈ ℂ → ( sin ‘ 𝐴 ) ∈ ℂ )
5 4 adantr ⊢ ( ( 𝐴 ∈ ℂ ∧ ( sin ‘ 𝐴 ) ≠ 0 ) → ( sin ‘ 𝐴 ) ∈ ℂ )
6 simpr ⊢ ( ( 𝐴 ∈ ℂ ∧ ( sin ‘ 𝐴 ) ≠ 0 ) → ( sin ‘ 𝐴 ) ≠ 0 )
7 3 5 6 divcld ⊢ ( ( 𝐴 ∈ ℂ ∧ ( sin ‘ 𝐴 ) ≠ 0 ) → ( ( cos ‘ 𝐴 ) / ( sin ‘ 𝐴 ) ) ∈ ℂ )
8 1 7 eqeltrd ⊢ ( ( 𝐴 ∈ ℂ ∧ ( sin ‘ 𝐴 ) ≠ 0 ) → ( cot ‘ 𝐴 ) ∈ ℂ )