Metamath Proof Explorer


Theorem dfid6

Description: Identity relation expressed as indexed union of relational powers. (Contributed by RP, 9-Jun-2020)

Ref Expression
Assertion dfid6 I = ( 𝑥 ∈ V ↦ 𝑛 ∈ { 1 } ( 𝑥𝑟 𝑛 ) )

Proof

Step Hyp Ref Expression
1 dfid4 I = ( 𝑥 ∈ V ↦ 𝑥 )
2 1ex 1 ∈ V
3 oveq2 ( 𝑛 = 1 → ( 𝑥𝑟 𝑛 ) = ( 𝑥𝑟 1 ) )
4 2 3 iunxsn 𝑛 ∈ { 1 } ( 𝑥𝑟 𝑛 ) = ( 𝑥𝑟 1 )
5 relexp1g ( 𝑥 ∈ V → ( 𝑥𝑟 1 ) = 𝑥 )
6 4 5 eqtrid ( 𝑥 ∈ V → 𝑛 ∈ { 1 } ( 𝑥𝑟 𝑛 ) = 𝑥 )
7 6 mpteq2ia ( 𝑥 ∈ V ↦ 𝑛 ∈ { 1 } ( 𝑥𝑟 𝑛 ) ) = ( 𝑥 ∈ V ↦ 𝑥 )
8 1 7 eqtr4i I = ( 𝑥 ∈ V ↦ 𝑛 ∈ { 1 } ( 𝑥𝑟 𝑛 ) )