Metamath Proof Explorer


Theorem elpwg

Description: Membership in a power class. Theorem 86 of Suppes p. 47. See also elpw2g . (Contributed by NM, 6-Aug-2000) (Proof shortened by BJ, 31-Dec-2023)

Ref Expression
Assertion elpwg ( 𝐴𝑉 → ( 𝐴 ∈ 𝒫 𝐵𝐴𝐵 ) )

Proof

Step Hyp Ref Expression
1 sseq1 ( 𝑥 = 𝑦 → ( 𝑥𝐵𝑦𝐵 ) )
2 sseq1 ( 𝑦 = 𝐴 → ( 𝑦𝐵𝐴𝐵 ) )
3 df-pw 𝒫 𝐵 = { 𝑥𝑥𝐵 }
4 1 2 3 elab2gw ( 𝐴𝑉 → ( 𝐴 ∈ 𝒫 𝐵𝐴𝐵 ) )