Metamath Proof Explorer


Theorem fundcmpsurinjlem3

Description: Lemma 3 for fundcmpsurinj . (Contributed by AV, 3-Mar-2024)

Ref Expression
Hypotheses fundcmpsurinj.p ⊢ 𝑃 = { 𝑧 ∣ ∃ 𝑥 ∈ 𝐴 𝑧 = ( ◡ 𝐹 “ { ( 𝐹 ‘ 𝑥 ) } ) }
fundcmpsurinj.h ⊢ 𝐻 = ( 𝑝 ∈ 𝑃 ↦ ∪ ( 𝐹 “ 𝑝 ) )
Assertion fundcmpsurinjlem3 ( ( Fun 𝐹 ∧ 𝑋 ∈ 𝑃 ) → ( 𝐻 ‘ 𝑋 ) = ∪ ( 𝐹 “ 𝑋 ) )

Proof

Step Hyp Ref Expression
1 fundcmpsurinj.p ⊢ 𝑃 = { 𝑧 ∣ ∃ 𝑥 ∈ 𝐴 𝑧 = ( ◡ 𝐹 “ { ( 𝐹 ‘ 𝑥 ) } ) }
2 fundcmpsurinj.h ⊢ 𝐻 = ( 𝑝 ∈ 𝑃 ↦ ∪ ( 𝐹 “ 𝑝 ) )
3 2 a1i ⊢ ( ( Fun 𝐹 ∧ 𝑋 ∈ 𝑃 ) → 𝐻 = ( 𝑝 ∈ 𝑃 ↦ ∪ ( 𝐹 “ 𝑝 ) ) )
4 imaeq2 ⊢ ( 𝑝 = 𝑋 → ( 𝐹 “ 𝑝 ) = ( 𝐹 “ 𝑋 ) )
5 4 unieqd ⊢ ( 𝑝 = 𝑋 → ∪ ( 𝐹 “ 𝑝 ) = ∪ ( 𝐹 “ 𝑋 ) )
6 5 adantl ⊢ ( ( ( Fun 𝐹 ∧ 𝑋 ∈ 𝑃 ) ∧ 𝑝 = 𝑋 ) → ∪ ( 𝐹 “ 𝑝 ) = ∪ ( 𝐹 “ 𝑋 ) )
7 simpr ⊢ ( ( Fun 𝐹 ∧ 𝑋 ∈ 𝑃 ) → 𝑋 ∈ 𝑃 )
8 funimaexg ⊢ ( ( Fun 𝐹 ∧ 𝑋 ∈ 𝑃 ) → ( 𝐹 “ 𝑋 ) ∈ V )
9 8 uniexd ⊢ ( ( Fun 𝐹 ∧ 𝑋 ∈ 𝑃 ) → ∪ ( 𝐹 “ 𝑋 ) ∈ V )
10 3 6 7 9 fvmptd ⊢ ( ( Fun 𝐹 ∧ 𝑋 ∈ 𝑃 ) → ( 𝐻 ‘ 𝑋 ) = ∪ ( 𝐹 “ 𝑋 ) )