Metamath Proof Explorer


Theorem fundcmpsurinjlem3

Description: Lemma 3 for fundcmpsurinj . (Contributed by AV, 3-Mar-2024)

Ref Expression
Hypotheses fundcmpsurinj.p ⊢ P = z | ∃ x ∈ A z = F -1 F ⁡ x
fundcmpsurinj.h ⊢ H = p ∈ P ⟼ ⋃ F p
Assertion fundcmpsurinjlem3 ⊢ Fun ⁡ F ∧ X ∈ P → H ⁡ X = ⋃ F X

Proof

Step Hyp Ref Expression
1 fundcmpsurinj.p ⊢ P = z | ∃ x ∈ A z = F -1 F ⁡ x
2 fundcmpsurinj.h ⊢ H = p ∈ P ⟼ ⋃ F p
3 2 a1i ⊢ Fun ⁡ F ∧ X ∈ P → H = p ∈ P ⟼ ⋃ F p
4 imaeq2 ⊢ p = X → F p = F X
5 4 unieqd ⊢ p = X → ⋃ F p = ⋃ F X
6 5 adantl ⊢ Fun ⁡ F ∧ X ∈ P ∧ p = X → ⋃ F p = ⋃ F X
7 simpr ⊢ Fun ⁡ F ∧ X ∈ P → X ∈ P
8 funimaexg ⊢ Fun ⁡ F ∧ X ∈ P → F X ∈ V
9 8 uniexd ⊢ Fun ⁡ F ∧ X ∈ P → ⋃ F X ∈ V
10 3 6 7 9 fvmptd ⊢ Fun ⁡ F ∧ X ∈ P → H ⁡ X = ⋃ F X